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otez555 [7]
2 years ago
8

What is the diameter of a hemisphere with a volume of 651 m^3, to the nearest tenth of a meter?

Mathematics
1 answer:
Sphinxa [80]2 years ago
5 0

Answer: 13.5 m, hope this helps :)

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The graph shows the linear relationship between the height of a plant (in centimeters) and the time (in weeks) that the plant ha
bija089 [108]
I found a graph with the same problem, so I guess this is the graph to be based on. To find the rate, just determine the slope between any two points along the line. Suppose these points are: (30,10) and (50,20).

Slope = (20 - 10)/(50 - 30) = 1/2

<em>The correct answer should be: the rate of change is 1 cm per 2 weeks, or 1/2.</em>

5 0
2 years ago
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It takes 8 minutes for Byron to fill the kiddie pool in the backyard using only a handheld hose. When his younger sister is impa
andreyandreev [35.5K]

Let us say that the procedure of completely filling up the pool with water is called “1 job”. Therefore the rates of the equipment in doing the job would be:

<span>Rate of handheld hose = 1 job / 8 minutes                  ---> 1</span>

<span>Rate of lawn sprinkler = r                                             ---> 2</span>

<span>Rate of the two combines = 1 job/ 5 minutes               ---> 3</span>

So we are to find the equation to use, in this case, we simply have to add equations 1 and 2 to get 3:

1 / 8 + r = 1 / 5

Multiplying both sides by 5:

<span>(5 / 8) + 5 r = 1                                                               ---> ANSWER</span>

8 0
2 years ago
Read 2 more answers
Find the measure of each indicated angle
Anna007 [38]
I think the answer would be 24 but im not 100% sure

7 0
1 year ago
David proved the Law of Cosines with reference to ∆ABC using a different method. Arrange the steps of his proof in the correct s
AURORKA [14]

Answer: We can arrange the steps with help of below explanation.  

Step-by-step explanation:

Here ABC is a triangle,

Draw a perpendicular from BD to side AC ( construction)

where D\in AC

In the right triangle BCD, from the definition of cosine:

cos C =CD/ BC

CD= a cos C

Subtracting this from the side b, we see that

DA= b-acos C  

In the triangle BCD, from the definition of sine:

sin C =BD  / a

BD = a sin C  

In the triangle ADB, applying the Pythagorean Theorem

c^2  =BD^2 +DA^2  

Substituting for BD and DA from (2) and (3)

c^2 =(asinC)^2 +(b-acosC)^2  

⇒c^2 =a^2sin ^2C+b^2-2ab cosC+a^2 cos ^2C   ( On simplification)

⇒c^2 =a^2sin ^2C+a^2 cos ^2C+b^2-2abcos C

⇒c^2=a^2(sin^2C+cos^2C) +b^2-2abcosC

⇒c^2 = a^2+b^2-2abcosC (because,sin^2\theta+cos^2\theta =1 )


3 0
2 years ago
A firkin is an old British unit of volume equal to 9 gallons. How many cubic meters are there in 6.00 firkins?
Rainbow [258]

Answer:

0.245489 cubic meters.

Step-by-step explanation:

It is given that a firkin is an old British unit of volume equal to 9 gallons.

1 firkin = 9 gallons

6 firkins = 54 gallons

We need convert 6.00 firkins to cubic meters.

We know that,

1 gallon = 0.00454609 cubic meters

54 gallon = 0.24548886 cubic meters

6 firkins = 0.245489 cubic meters.

Therefore, 6.00 firkins is equivalent to 0.245489 cubic meters.

7 0
2 years ago
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