A parking garage charges a fixed amount of money for each hour that it is used.

Suppose 50 percent of the customers at Pizza Palooza order a square pizza, 70 percent order a soft drink, and 35 percent order b

Firdavs [7]

Answer:

Ordering a soft drink is independent of ordering a square pizza.

Step-by-step explanation:

20% more customers order a soft drink than pizza, therefore they cannot be intertwined.

Given: P(A)=0.5 & P(B)=.7

P(A∩B) = P(A) × P(B)

= 0.5 × .7

= 0.35

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.5 + .7 - 0.35

= 0.85

P(AΔB) = P(A) + P(B) - 2P(A∩B)

= 0.5 + .7 - 2×0.35

= 0.5

P(A') = 1 - P(A)

= 1 - 0.5

= 0.5

P(B') = 1 - P(B)

= 1 - .7

= 0.3

P((A∪B)') = 1 - P(A∪B)

= 1 - 0.85

= 0.15

7 0

2 years ago

The telephone company is planning to introduce two new types of executive communications systems that it hopes to sell to its la

cluponka [151]

Answer:

x = 31 hundred dolars and

y = 91/2 = 45.5 hundred dolars

Step-by-step explanation:

Given

R(x) = (40−8x+5y)*x + (50+9x−7y)*y

C(x) = (40−8x+5y)*10 + (50+9x−7y)*29

We can use the equation

P(x) = R(x) - C(x)

where

P(x) is the profit

R(x) is the revenue

and C(x) is the costs

In order to maximize the telephone company's profit, we apply

P'(x) = R(x)' - C(x)' = 0

⇒ R(x)' = ((40−8x+5y)*x + (50+9x−7y)*y)' = (40x-8x²+14xy+50y-7y²)'

⇒ C(x)' = ((40−8x+5y)*10 + (50+9x−7y)*29)' = (1850+181x-153y)'

⇒ P'(x) = -8x²-7y²-141x+203y+14xy-1850

The first-order partial derivatives of these functions are

Px(x,y) = -16x-141+14y

Py(x,y) = -14y+203+14x

Setting these equal to zero and solving we obtain:

-16x+14y-141 = 0

14x-14y+203=0

we get the solution

x = 31 and y = 91/2 = 45.5

Finally, the company should produce 3100 units of the first system, and 4550 units of the second system.

8 0

2 years ago

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y

saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})$

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

= $(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})$

Combining all the like terms, we get as

= $(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}$

= $-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}$

Option A is the correct answer.

6 0

2 years ago

Read 2 more answers

Bob Rohrman is offering a 2016 Toyota Camry for $29,000. If you have a $5,000 down payment and are able to borrow the rest at a

vova2212 [387]

Answer:

The monthly payment will be $531.12

Step-by-step explanation:

Consider the provided information.

After paying $5,000 down payment you need to pay:

$29,000-$5,000=$24,000

APR is 2.99% or APR = 0.299%

Therefore, $r=\frac{0.0299}{12}$

n = 48

We can calculate the monthly payment by using the formula:

$P=\frac{r(PV)}{1-(1+r)^{-n}}$

Where P is the monthly payment, PV is the present value, r is the rate per period and n is the number of period.

Substitute the respective values in the above formula we get,

$P=\frac{\frac{0.0299}{12}(24000)}{1-(1+\frac{0.0299}{12})^{-48}}$

$P=\frac{59.8}{0.112593}$

$P\approx531.12$

Hence, the monthly payment will be $531.12

4 0

2 years ago

Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.

Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

$A=\frac{3\sqrt{3} }{2} r^2$

Where $r$ is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid: $A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2$

From these areas we find the radius of the hexagons:

$r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}$

$r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}$

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that $r_1$ $r_2$ form similar triangles with length $H$

Therefore we have:

$\frac{H-8}{r_1} =\frac{H}{r_2}$

We put in the numerical values of $r_1$ , $r_2$ and solve for $H$ :

$\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}$

8 0

2 years ago