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Maksim231197 [3]
2 years ago
6

The diagram shows two different buttons and their weights.

Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:8

Step-by-step explanation:

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Felicia wanted to find the number of boys in the school band if 30% of the 50 students are boys. Is her answer correct? Explain
docker41 [41]

Answer:

Creo que con 15

Step-by-step explanation:

50 -------> 100%

X ---------> 30%

X = (50*30)/100

X= 15 boys

4 0
2 years ago
Read 2 more answers
If a baker doubles a recipe that calls for 6-2/3 cups of flour. How many cups will be needed in all?
nadya68 [22]
Hey there!

The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1. 

6 \frac{2}{3}  = 6*3+2 =  \frac{20}{3}

\frac{20}{3} *  \frac{2}{1}

To multiply fractions, you can just multiply the numerators and denominators and simplify, if applicable. 

\frac{20}{3} * \frac{2}{1} = \frac{40}{3}

Since you can't simplify this fraction in its improper form, just convert it back into a mixed number. 

\frac{40}{3} = 13 \frac{1}{3}

So, your answer will be 13 \frac{1}{3}. 

Hope this helped you out! :-)
4 0
2 years ago
Read 2 more answers
In a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979,
Fed [463]

Answer:

we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

Step-by-step explanation:

Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.

Let X be the group married less than 2 years and Y less than 5 years

                         X        Y     Total

Sample size   300   300    600

Favouring       240   288    528

p                      0.8     0.96  0.88

H_0: p_x=p_y\\H_a: p_x>p_y

p difference = -0.16

Std error for difference = \sqrt{0.88*0.12/600} =0.01327

Test statistic = p difference/std error=-6.03

p value <0.000001

Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

4 0
2 years ago
Lisa says that the indicated angles cannot have the same measure. Marita disagrees and says she can prove that they can have the
AlexFokin [52]
I agree with Marita, that the angles could have the same measure.  This can be proven if you set the two amounts equal and solve for x. 

9x - 25 + x = x + 50 + 2x - 12

To begin, we should combine like terms on both sides of the equation to start simplifying the equation.

10x - 25 = 3x + 38

Next, we should subtract 3x from both sides and add 25 to both sides to get the variable x alone on the left side of the equation.

7x = 63

Finally, we should divide both sides by 7, to get rid of the coefficient of x.

x = 9

If you plug in 9 for x in our first equation, you get that both of the angle measurements equal 65 degrees.  This means that Marita is correct, because if x = 9, then the angles would have the same measure.


8 0
2 years ago
Simplify (5b)(-3a). -35ab -15ab 2ab
Fofino [41]
(5b)(-3a)
= (5*(-3))(b*a) (combine like terms)
= -15ab

The final answer is -15ab~
3 0
2 years ago
Read 2 more answers
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