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Gwar [14]
2 years ago
14

The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inche

s. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to:
Mathematics
2 answers:
FrozenT [24]2 years ago
7 0
70 inches. The answer is e. 70 inches.
gogolik [260]2 years ago
3 0

Answer:

69.65 inches

Step-by-step explanation:

Mean = \mu = 65

Standard deviation = \sigma = 2

Now we are supposed to find if Rachael is at the 99th percentile in height for adult women, then her height, in inches

Formula : z =\frac{x-\mu}{\sigma}

z at 99th percentile =2.326

Substitute the values in the formula

2.326=\frac{x-65}{2}

2.326 \times 2=x-65

4.652=x-65

4.652+65=x

69.65=x

Hence her height is 69.65 inches .

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