Question

The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inches. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to:

Answer 1

70 inches. The answer is e. 70 inches.

Answer 2

Answer:

69.65 inches

Step-by-step explanation:

Mean = $\mu = 65$

Standard deviation = $\sigma = 2$

Now we are supposed to find if Rachael is at the 99th percentile in height for adult women, then her height, in inches

Formula : $z =\frac{x-\mu}{\sigma}$

z at 99th percentile =2.326

Substitute the values in the formula

$2.326=\frac{x-65}{2}$

$2.326 \times 2=x-65$

$4.652=x-65$

$4.652+65=x$

$69.65=x$

Hence her height is 69.65 inches .