Answer:
(3,6)
Step-by-step explanation:
Given that Mila reads at a rate of 2 paragraphs per minute. After reading for 3 minutes, she had read a total of 6 paragraphs.
This situation can be represented with a linear equation written in slope-intercept form, as
where 'x' represents the number of minutes and,
y represents the number of paragraphs.
Since y intercept is 0 i.e. 0 paras in 0 minutes we have the equation as
Since no of minutes or paragraphs cannot take negative values this line is defined only in the I quadrant where both x and y are positive
Out of the points given as follows:
(3,6) (2,3) (-3,6) or (-2,6)
,
we can remove last two since they have negative x which is impossible.
Consider (3,6) (2,3)
Out of these only I point (3,6) satisfies and second point (2,3) does not satisfy
Hence answer is (3,6)
Answer:
Answer: 25 guests is 2.5 times more than 10
Multiply each order by 2.5
Chicken = 16 x 2.5 = 40
Lasagna = 7 x 2.5 = 17.5 , round to 18
Deli meat = 1.8 x 2.5 = 4.5, round to 5
Sliced cheese = 15 x 2.5 = 37.5, round to 38
Buns = 1 x 2.5 = 2.5, round to 3
Potato salad = 2 x 2.5 = 5
Step-by-step explanation:
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Answer:
8% out of 175 = ( 8 ÷ 100 ) × 175 = 14
175 cm - 14 = 161 cm
...............
Answer:
5.5
Step-by-step explanation:
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
so 5.5 minus 0
correct me if this is wrong
