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levacccp [35]
1 year ago
8

Hernando ate StartFraction 2 Over 8 EndFraction of a pizza for a dinner. He gave his 6 friends the rest of the pizza and told th

em to share it equally. To determine the fraction of the whole pizza that each of his friends received, Hernando performed the calculations below. StartFraction 6 Over 8 EndFraction divided by 6 = StartFraction (6 divided by 6) Over 8 EndFraction = one-eighth He concluded that each person received One-eighth of the whole pizza. Are Hernando's calculations correct? Explain why or why not. Yes, they are correct. Hernando divided 6 by 6. Yes, they are correct. Hernando divided Two-eighths by 6. No, they are not correct. Hernando should have multiplied by 6, not divided by 6. No, they are not correct. Hernando should have divided 8 by 6, not 6 by 6.
Mathematics
2 answers:
Akimi4 [234]1 year ago
8 0

Answer:

A Yes, they are correct. Hernando divided 6 by 6. on edge

Step-by-step explanation:

hope this helps:)

ozzi1 year ago
3 0

Answer:

Yes, they are correct. Hernando divided 6 by 6.

Step-by-step explanation:

Given that:

Hernando ate 2/8 of a pizza for dinner.

Let the pizza be x. Then:

Hernando ate \dfrac{2}{8} \ \ o f  \ \ x

Then he gave the rest of the pizza to his friends

Hernando now carried out the  following calculations to support his activities;

\dfrac{6}{8} \div 6= \dfrac{6 \div 6}{8}= \dfrac{1}{8}

\dfrac{6}{8} \times \dfrac{1}{6}= \dfrac{6 \div 6}{8}= \dfrac{1}{8}

From the above calculation; we will see that Hernando divided 6 by 6 in both cases to get \dfrac{1}{8}.

Thus, the correct answer is:

Yes, they are correct. Hernando divided 6 by 6.

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anzhelika [568]
<span>this is pretty hard but here is your answer 
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y = x^2 - 10x + 25 - 25

<span> y = (x-5)^2 - 25 </span>

<span> y+25 = (x-5)^2 </span>

<span> x-5 = +/-sqrt(y+25) </span>

 

<span> And you get TWO inverses: </span>

 

<span> x = 5 + sqrt(y+25), for x>=5 </span>

<span> x = 5 - sqrt(y+25), for x<=5</span>


5 0
2 years ago
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AT&amp;T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let x be the number of additional line.

Cost of one additional line = $15

Cost of x additional line = \$15x

Total cost = Fixed cost + Addition cost

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It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

8 0
2 years ago
What are the domain, range, and asymptote of h(x) = 6x – 4? domain: {x | x is a real number}; range: {y | y &gt; 4}; asymptote:
Mkey [24]

Answer:

Step-by-step explanation:

The domain of a function is the set for which the function is defined. Our function is the function h(x) = 6x-4. This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.

The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.

Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.

4 0
1 year ago
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A town council wants to estimate the proportion of residents who are in favor of a proposal to upgrade the computers in the town
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Answer:

Trying to help out, I think it's appropriate

Step-by-step explanation:

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riadik2000 [5.3K]

Answer:

a. (2.5,5)

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f(x) exponential function exceed quadratic function g(x) at (2.5 , 5)

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