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Paladinen [302]

2 years ago

9

Allison plays basketball and last season she made a total of 87 shots (two- or three- point shots). Her points total was 191. Ho

w many three-points shots did she make

1 answer:

yarga [219]2 years ago

4 0

Answer:

17

Step-by-step explanation:

Let the number of 2 point shots be t.

Let the number of 3 point shots be h.

Allison made 87 shots and scored 191 total points. This implies two things:

t + h = 87 ________(1)

2t + 3h = 191 ______(2)

Let us eliminate t by multiplying (1) by 2 and subtracting from (2):

=> 2t + 3h = 191

- <u>2t + 2h = 174</u>

<u> h = 17 </u>

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Therefore, she made 17 three point shots.

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Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep

Viktor [21]

<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. $3x+6y-12z=36$

2. $x+2y-4z=12$

3. $4x+8y-16z=48$

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with $x+2y-4z=12$ which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

6 0

1 year ago

What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.

Gnesinka [82]

First, we are going to use the law of cosines to find the length of the line segment FH:
$FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}$
$FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}$
$FH=3.2$

Next, we are going to use the semi-perimeter formula: $s= \frac{GH+FG+FH}{2}$
$s= \frac{2+2.5+3.2}{2}$
$s= \frac{7.7}{2}$
$s=3.9$

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
$A= \sqrt{s(s-GH)(s-FG)(s-FH)}$
$A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}$
$A= \sqrt{3.9(1.9)(1.4)(0.7)}$
$A=2.7m^{2}$

We can conclude that the area of the triangle <span>GHF is 2.7 </span> $m^{2}$ .

3 0

2 years ago

One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t

kozerog [31]

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function $f(x) = x^3-8x^2 + 17x-10$ is $(x-5).$

Factor the polynomial in the following way:

$x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)$

Now factor the quadratic in brackets:

$x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)$

Hence,

$f(x)=(x-5)(x-2)(x-1)$

The x-intercepts are points at which y = 0, so

$(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1$

The y-intercepts are points at which x = 0, so

$y=0^3-8\cdot 0^2+17\cdot 0-10=-10$

4 0

1 year ago

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Given: circle O with tangent AB mBC= 2x -16; mCD = x+40; mDE = x; mEB = 60 <br><br>find the x

murzikaleks [220]

Answer:

69

Step-by-step explanation:

All the given arcs cover the entire circle circumference, so their measures add up to a full 360.

(2x - 16) + (x + 40) + x + 60 = 360

4x + 84 = 360

4x = 276

x = 69

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2 years ago

LK is tangent to circle J at point K. What is the length of the radius? 6/25 85/12 121/36 157/12

schepotkina [342]

Answer:

85/12

Step-by-step explanation:

4 0

1 year ago

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