The side of the congruent side of the triangle should be greater than 7 feet.
m□ebd=4 x-8 and m□ebc=5 x+20
This is solvable only if e b is the initial side and b d and b c lies on opposite side of each other and lies on a line i.e c,b,d are Collinear.
∠ebd and ∠ebc will form a linear pair.The meaning of linear pair is that angles forming on one side of a straight line through a common vertex which are adjacent is 180°.
i.e
∠ ebd + ∠ebc = 180°
4 x- 8 + 5x + 20= 180°
adding like terms
⇒ 9 x +12 =180°
⇒ 9 x = 180° - 12
⇒ 9 x = 168°
⇒ x =( 168/9)°=(56/3)°
now m□ebc =5 x +20
= 5 × 56/3 + 20
= 280/3 + 20
=340/3
m□ebc=( 340/3)°
So, solution set is x =(56/3)° and m□ebc =(340/3)°
Mason compared the number of free throws made to the number of free throws missed. The probability would actually be 2/5 becahse 18+12 is 30, giving you your denominator, then you made 12. So, simplifying 12/30 gives you your probability of 2/5.
Hope this helps you!
From the given above, we will include the case in which 3 and all 4 defectives are included in the purchase.
For 3:
(36C5) x (4C3) = 1507968
For 4:
(36C4) x (4C4) = 58905
Adding these numbers will give us an answer of 1566873.
Answer:
Step-by-step explanation:
Given that transitor has a 2% defective rate, need to calculate the probability that the 10th transistor produced is the first with a defect.
The probability function is p(x=k) = (1-p)^(n-1) * p
p = (1-defective rate)^(n-1) * defective rate; n=10
p = (1-0.02)^9 * 0.02 = 0.98^9 * 0.02 = 0.01666