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Ahat [919]
2 years ago
6

(05.02 MC) The figure below shows a line graph and two shaded triangles that are similar: A line is shown on a coordinate grid.

The x-axis values are from negative 10 to positive 10 in increments of 2 for each grid line. The y-axis values are from negative 5 to positive 5 in increments of 1 for each grid line. The line passes through the ordered pairs negative 8, 4, and 0, 0, and 8, negative 4. A shaded right triangle is formed so that its hypotenuse is from ordered pair 0, 0 labeled as O to negative 4, 2 labeled as A, one leg is from 0, 0 to negative 4, 0, and the second leg is from negative 4, 0 to negative 4, 2. Another shaded right triangle is formed with the hypotenuse from negative 4, 2 to negative 6, 3, labeled as B, one leg is from negative 4, 2 to negative 6, 2, and the second leg is between negative 6, 2 to negative 6, 3. Which statement about the slope of the line is true? It is −2 throughout the line. It is fraction negative 1 over 2 throughout the line. The slope from point O to point A is fraction 1 over 2 times the slope of the line from point A to point B. The slope from point O to point A is two times the slope of the line from point A to point B.
Mathematics
2 answers:
HACTEHA [7]2 years ago
7 0

Answer:

the answer is d i hope this was a help to your problem some how.

Step-by-step explanation:

Elenna [48]2 years ago
5 0

Answer:

D

Step-by-step explanation:

i got you its just <em>D</em>.<em> <3</em>

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rodikova [14]
Volume of cone = 1/3 x pi x r^2 x h
where r = 5 ft and h = 16ft

Volume = 1/3 x pi x 5^2 x 16 = 400/3 π ft^3
6 0
1 year ago
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A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 9 1/3 squar
Vika [28.1K]
Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd

Area of parallelogram = base * height

We need to divide the combined area into two to get each parallelogram's base.

9 1/3 = ((9*3)+1)/3 = 28/3

28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²

Area of each parallelogram is 4 2/3 yd²

4 2/3 yd² = base * 1 1/3 yd

14/3 yd² ÷ 4/3 yd = base

14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base

a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.

length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds

Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²


8 0
1 year ago
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If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?
kiruha [24]

Answer:

[1,\infty)

Step-by-step explanation:

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a(x)=3x+1

Since we want to know the domain of (b \circ a)(x), let's first consider the domain of the inside function, that is, that of a(x)=3x+1. Every polynomial function has domain all real numbers.

So we can plug anything for function a and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find (b \circ a)(x) and simplify now.

(b \circ a)(x)

b(a(x))

b(3x+1)

\sqrt{(3x+1)-4}

\sqrt{3x+1-4}

\sqrt{3x-3}

Now again we can only square root positive or zero numbers so we want 3x-3 \ge 0.

Let's solve this to find the domain of (b \circ a)(x).

3x-3 \ge 0

Add 3 on both sides:

3x \ge 3

Divide both sides by 3:

x \ge 1

So we want x to be a number greater than or equal to 1.

The option that says this is [1,\infty)

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(-2)=3(-2)+1=-6+1=-5 and b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}.

Give an example why option B fails:

A number in the given set is 0.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(0)=3(0)+1=0+1=1 and b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}.

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(3)=3(3)+1=9+1=10 and b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}.

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What weight of dry substance is in 150g of a 3% substance solution? What weight of an 8% solution can we have with the same weig
Pavlova-9 [17]
The answers are: 4.5 g and 56.25 g respectively.

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5 0
1 year ago
The diameters of aluminum alloy rods produced on an extrusion machine are known to have a standard deviation of 0.0001 in. A ran
Ganezh [65]

Answer:

a) Hypothesis mean differs from 0.5025. Rejected

b) P-value = 0

c) 0.50456 < u < 0.50464

Step-by-step explanation:

Given:

- The standard deviation s.d = 0.0001 in

- The mean of the sample x = 0.5046 in

- Sample size n = 25

Find:

a) Test the hypothesis that mean rod. Assume two-sided alternative and significance level of 0.05.

b) Find the p-value for test in part

c) Construct a 95% two-sided confidence interval on the mean rod diameter.

Solution:

- The random variable X: the measurements for rod diameter follows a normal distribution:  

                                       X~ N( 0.5025 , 0.0001 )

- Testing H_o: u_o = 0.5025  , H_1 : u_o not equal 0.5025

- Compute the corresponding Z-score:

                             Z_o = (0.5046 - 0.5025) / 0.0001/sqrt(25)

                             Z_o = 105

- The Z score value with respect to significance level is:

                            Z_a/2 = Z_0.025 = 1.96

Hence, Z_o > Z_a/n

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- The corresponding P-Value is:

                            P-value = 2*(1 - sig(Z_o)) = 2*(1 - sig(105))

                           P-value = 2*(1-1) = 0

- The confidence interval is:

                 ( x - Z_a/2(s.d/sqrt(n)) < u <  ( x + Z_a/2(s.d/sqrt(n))

  ( 0.5046 - 1.96(0.0001/sqrt(25)) < u <  ( 0.5046 + 1.96(0.0001/sqrt(25))  

                              0.50456 < u < 0.50464

3 0
2 years ago
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