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Olegator [25]
2 years ago
9

Suppose a system has two modules, A and B, that function independently. Module A fails with probability 0.24 and Module B fails

with probability 0.38, when the system is executed. When the system is executed, find the probability that.
(a) only Module A fails (b) only Module B fails. (c) both modules fail. (d) neither module fails. (e) What do the probabilities add up to?
Mathematics
1 answer:
DiKsa [7]2 years ago
4 0

Answer:

Idk idk idk idk idk idk idk idk

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The following data represent weights in kilograms of maize harvest from a random sample of 72 experimental plots on St. Vincent,
Scrat [10]

Answer:

See explanation

Step-by-step explanation:

7.8 9.1 9.5 10.0 10.2 10.5 11.1 11.5 11.7 11.8

12.2 12.2 12.5 13.1 13.5 13.7 13.7 <u>14.0 14.4</u> 14.5

14.6 15.2 15.5 16.0 16.0 16.1 16.5 17.2 17.8 18.2

19.0 19.1 19.3 19.8 20.0 20.2 20.3 20.5 20.9 21.1

21.4 21.8 22.0 22.0 22.4 22.5 22.5 22.8 22.8 23.1

23.1 23.2 23.7 <u>23.8 23.8</u> 23.8 23.8 24.0 24.1 24.1

24.5 24.5 24.9 25.1 25.2 25.5 26.1 26.4 26.5 26.7

27.1 29.5

A. The five-number summary is

  • Minimum = 7.8
  • Maximum = 29.5
  • Median =\dfrac{20.2+20.3}{2}=20.25
  • Q_1=\dfrac{14.0+14.4}{2}=14.2
  • Q_3=\dfrac{23.8+23.8}{2}=23.8

B. The interquartile range is

Q_3-Q_1=23.8-14.2=9.6

C. See attached diagram

D. The distribution is not symmetric, the left half shows more data than the right part

7 0
2 years ago
From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
zhenek [66]
1.3/13(if you mean jacks queens and kings)
2.1/52
3.1/2
4.1/13
5.1/4
8 0
2 years ago
Read 2 more answers
The number of children in each family on a particular city block is shown in the dot plot: Dot plot with Number of Children Per
Crank

Answer:

Step-by-step explanation:

Hi,

I think the options are missing for this question.

The x-axis shows the number of children per family and y-axis shows the frequency or number of families with respective number of children.

A histogram simply displays the data with bars of different heights. The higher the frequency, the taller the bar of the histogram and vice versa.

Your histogram should look like this.

5 0
2 years ago
Read 2 more answers
The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc
gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}

Write W in terms of U and V.

\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}

Define U and V using geometric series formula.

\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}

Use sum of geometric series formula.

2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})

Simplify.

-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})

Therefore, r = 9 and m = 112.

8 0
2 years ago
The shape below is constructed from six squares, and the lengths of the sides of the three smallest squares are written inside o
Maurinko [17]

Answer:

78

Step-by-step explanation:

Smallest square: 1

Small Square: 2, Area of 4

Mid Square: 3, Area of 9

Mid White Square: 5, Area of 25

Big Square: 8, Area of 64

1 + 4 + 9 + 64 = 78

5 0
2 years ago
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