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Olegator [25]
2 years ago
9

Suppose a system has two modules, A and B, that function independently. Module A fails with probability 0.24 and Module B fails

with probability 0.38, when the system is executed. When the system is executed, find the probability that.
(a) only Module A fails (b) only Module B fails. (c) both modules fail. (d) neither module fails. (e) What do the probabilities add up to?
Mathematics
1 answer:
DiKsa [7]2 years ago
4 0

Answer:

Idk idk idk idk idk idk idk idk

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Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar
ella [17]

Cost of chicken wings at Buffalo Bills = 8 wings for $7

Cost of 1 wing at Buffalo Bills = \frac{7}{8} =0.875

Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10

Cost of 1 wing at Buffalo Mild Wings = \frac{10}{12}= 0.833

Cost of chicken wings at Wingers = 20 wings at $17

Cost of 1 wing at Wingers = \frac{17}{20}= 0.850

Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.

8 0
1 year ago
Read 2 more answers
Find the measure of each indicated angle
Anna007 [38]
I think the answer would be 24 but im not 100% sure

7 0
1 year ago
What is the quotient? 5/4c^2÷15/7c assume c is not equal to 0​
BaLLatris [955]

Answer:

<em>The quotient is \frac{7}{12c}</em>

Step-by-step explanation:

Given expression is:  \frac{5}{4c^2}\div \frac{15}{7c}

<em>While dividing two fractions, first we need to change the division sign into multiplication and then flip the second fraction. </em>

So, we will get.....

\frac{5}{4c^2}\div \frac{15}{7c}\\ \\ =\frac{5}{4c^2}\times \frac{7c}{15}\\ \\ =\frac{35c}{60c^2}\\ \\ = \frac{7}{12c} \ \ [Dividing\ both\ numerator\ and\ denominator\ by\ 5c]

So, the quotient is \frac{7}{12c}

4 0
2 years ago
If EF bisects CD, CG = 5x-1, GD = 7x-13, EF=6x-4, and GF = 13, find EG (MUST SHOW WORK)
iogann1982 [59]

Answer:

EG = 19

Explanation:

Given that a line segment CD. EF bisects the line CD at point G.

Length of CG = 5x-1

Length of GD = 7x - 13

We know that CG = GD

5x-1 = 7x-13

Solve for x,

2x = 12

x = 6

Now given that,

EF = 6x-4

GF = 13

EF = EG + GF

6x - 4 = EG + 13

EG = 6x - 4 - 13

EG = 6x - 17

put the value of x = 6, in order to find the EG

EG = 6*6 - 17

EG = 19

That's the final answer.

I hope it will help you.

3 0
1 year ago
The energy expended by a bird per day, E, depends on the time spent foraging for food per day, F hours. Foraging for a shorter t
Veronika [31]

Answer:

Therefore F=2.387 hours gives a minimum value of energy expenditure E.

Step-by-step explanation:

Given that,

The energy expended by a bird per day

E=0.25 F+\frac{1.7}{F^2}

Differentiating with respect to F

E'=0.25 -\frac{3.4}{F^3}

Again differentiating with respect to F

E''=\frac{10.2}{F^4}

Now set E'=0

0.25 -\frac{3.4}{F^3}=0

\Rightarrow \frac{3.4}{F^3}=0.25

\Rightarrow F^3=\frac{3.4}{0.25}

\Rightarrow F=2.387

Now E''|_{F=2.387}=\frac{10.2}{2.387^4}>0

Since, E''>0 at F=2.387, So at F=2.387 , E has minimum value.

Therefore F=2.387 hours that minimizes energy expenditure.

7 0
1 year ago
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