Which fraction is equivalent to fraction with numerator 6 and denominator negative 8? fraction with numerator negative 8 and den
2 answers:
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Refer to the diagram below.
Because ray NP bisects ∠MNQ, therefore
∠MNP = ∠PNQ = 2x + 1.
Therefore
∠MNQ = 2*∠PNQ = 2(2x + 1) = 4x + 2.
Because ∠MNQ is given as x² - 10, therefore
x² - 10 = 4x + 2
x² - 4x - 12 = 0
(x + 2 )(x - 6) = 0
x = -2, or x = 6
When x = -2,
∠MNQ = 4*(-2) + 2 = -6°
This answer is not acceptablle, therefore x = -2 should be rejected.
When x = 6,
∠MNQ = 4*6 + 2 = 26°
Answer: x = 6, and ∠MNQ = 26°
Because ray NP bisects ∠MNQ, therefore
∠MNP = ∠PNQ = 2x + 1.
Therefore
∠MNQ = 2*∠PNQ = 2(2x + 1) = 4x + 2.
Because ∠MNQ is given as x² - 10, therefore
x² - 10 = 4x + 2
x² - 4x - 12 = 0
(x + 2 )(x - 6) = 0
x = -2, or x = 6
When x = -2,
∠MNQ = 4*(-2) + 2 = -6°
This answer is not acceptablle, therefore x = -2 should be rejected.
When x = 6,
∠MNQ = 4*6 + 2 = 26°
Answer: x = 6, and ∠MNQ = 26°
Answer:
1)
Using the condition given:
So then if we want to create an equation we need to do this:
With K a constant. For this case the period of a pendulumn is given by this general expression:
Where L is the length in m and g the gravity .
2)
If we square both sides of the equation we got:
And solving for L we got:
Replacing we got:
3)
Step-by-step explanation:
Part 1
For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.
Using the condition given:
So then if we want to create an equation we need to do this:
With K a constant. For this case the period of a pendulumn is given by this general expression:
Where L is the length in m and g the gravity .
Part 2
For this case using the function in part a we got:
If we square both sides of the equation we got:
And solving for L we got:
Replacing we got:
Part 3
For this case using the function in part a we got:
Replacing we got: