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2 years ago

What else would need to be congruent to show that STU is congruent to JKL by SAS? tysm! :)

Mathematics

2 answers:

lyudmila [28]2 years ago

7 0

Answer:

Choice C.

Step-by-step explanation:

You already have two sides and two angles. Now you need the other two sides that include the angle. Choice C is correct.

Fittoniya [83]2 years ago

3 0

Answer: C. $\overline{SU}\cong\overline{JL}$

Step-by-step explanation:

SAS congruence postulate tells that if two sides and the included angle of a triangle are congruent to corresponding two sides and the included angle of other triangle, then the triangles are congruent.

In the given picture , we have two triangles ΔSTU and Δ JKL , in which we have

$\overline{ST}\cong\overline{JK}$

$\angle{S}\cong\angle{J}$

To prove ΔSTU is congruent to Δ JKL, we need $\overline{SU}\cong\overline{JL}$ such that $\angle{S}\text{ and }\angle{J}$ becomes congruent the included angles between pair of congruent sides.

Hence, C is the right option.

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What is the solution set for - 4x + 10 = 5(x + 11)? HELPPPPPPP

Scorpion4ik [409]

Answer:

-5

Step-by-step explanation:

-4x +10 =5(x +11)

-4x +10 =5x +55

-4x - 5x =55 - 10

-9x =45

x=-45 :9

x=-5

7 0

2 years ago

Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct? Explain. triangular

evablogger [386]

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

The given information are;

A triangular prism lying on a rectangular base and a line drawn along the slant height

A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces

Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).

8 0

2 years ago

Read 2 more answers

In an athletics team, tall members are three times more likely to win a medal than short members. this year the team has won 60

nirvana33 [79]

Well lets say y = the amount of medals won. lets say x is the amount won by short people and z is the amount won by tall. we know that the total medals is the total medals won by short and tall so:
y = x + z

it says that tall people are 3.times more likely. this would mean they won three times more than short people. so
z = 3x.

so if we know what z equals, we can replace z with what it is equal to. so:
y = x + z
y = x + 3x
y = 4x

we know that 60 medals were won so
y = 4x
60 = 4x
x = 15

that is the amount won by short people

4 0

2 years ago

The average annual costs for owning two different refrigerators for x years is given by the two functions: f(x) = 850 + 62x /x a

Alex17521 [72]

Answer:

In the long run cost of the refrigerator g(x) will be cheaper.

Step-by-step explanation:

The average annual cost for owning two different refrigerators for x years is given by two functions

f(x) = $\frac{850+62x}{x}$

= $\frac{850}{x}+62$

and g(x) = $\frac{1004+51x}{x}$

= $\frac{1004}{x}+51$

If we equate these functions f(x) and g(x), value of x (time in years) will be the time by which the cost of the refrigerators will be equal.

At x = 1 year

f(1) = 850 + 62 = $912

g(1) = 1004 + 51 = $1055

So initially f(x) will be cheaper.

For f(x) = g(x)

$\frac{850}{x}+62$ = $\frac{1004}{x}+51$

$\frac{1004}{x}-\frac{850}{x}=1004-850$

$\frac{154}{x}=11$

x = $\frac{154}{11}=14$

Now f(15) = 56.67 + 62 = $118.67

and g(x) = 66.93 + 51 = $117.93

So g(x) will be cheaper than f(x) after 14 years.

This tells below 14 years f(x) will be less g(x) but after 14 years cost g(x) will be cheaper than f(x).

5 0

2 years ago

Read 2 more answers

4. The data shows the number of siblings each student in a 9th-grade class has.

antiseptic1488 [7]

Answer:

The correct option is Mean and standard deviation.

Step-by-step explanation:

The data set provided, arranged in ascending order is:

S = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 4}

Now, it is provided that Macy was absent when the data was collected and the class guessed she had 4 siblings. When she returned, they found out she actually has 9 siblings.

So, the new data set is:

X = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 9}

The mean of a data set is the average value representing the entire data.

$\bar X=\frac{1}{n}\sum X_{i}$

The median is the middle value of the data set.

The inter-quartile range is the difference between the first and the third quartile.

The standard deviation is the value that represents how dispersed the data values are.

$SD=\sqrt{\frac{1}{n}\sum (X_{i}-\bar X)^{2}}$

From all the above statistic, the mean and standard deviation are the only ones that uses all the observations in the data set to compute their value.

So, on changing one of the 4s by a 9, the set of measures that will be affected are the mean and standard deviation.

Thus, the correct option is Mean and standard deviation.

3 0

2 years ago