Question

What is the sum of the polynomials (-x^2+9)+(3x^2-11x+4)

Answer 1

Hello!

The answer is:

$(-x^{2}+9)+(3x^2-11x+4)=2x^{2}-11x+13$

Why?

To solve the problem, we must remember how to add/subtract like terms. The like terms are the terms that share the same variable and the same exponent.

For example:

$2x+3x+x^{2}=x^{2}+(2x+3x)=x^{2}+5x$

We were able to add only the linear terms (terms that contains the variable x") because they were like terms: they share the same variable and the same exponent.

We need to perform the following operation between polynomials:

$(-x^{2}+9)+(3x^2-11x+4)$

So, calculating we have:

$(-x^{2}+9)+(3x^2-11x+4)=2x^{2}-11x+13$

Have a nice day!

Answer 2

You add up all of the numbers with same coefficients. so that would be ( 2x^2-11x+13) bc -x^2 + 3x^2 is 2x^2, -11x stays the same because there is no other x, and 9+4 is 13 :)