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2 years ago

If 1/6x+2/3y=8 what is the value of 2x+8y

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

7 0

Answer: 96

Step-by-step explanation:

Simply multiply the first question by 12 to get 2x+8y=96

<em>Hope it helps <3</em>

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) If the pattern shown continues, how many black keys appear on a portable keyboard with 49 white keys? Suggestion: use equivale

andriy [413]

Answer:

Step-by-step explanation:

Here we see 5 black keys for every 7 white keys.

So the ratio is 5:7

If we need 49 white keys, find the amount we scale the original ratio by:

49/7 = 7

So we are scaling by a factor of 7.

The number of black keys would be 5 * the scale of 7. = 35

So there should be 35 black keys.

5 0

1 year ago

Read 2 more answers

Kourtney and Kayla are sisters who are taking the same classes this semester: MAT 003, CHM 131/3131A, and ACA 122. if kourtney e

qaws [65]

Answer: A.3.5

Step-by-step explanation: because i said

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2 years ago

Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif

Nadusha1986 [10]

Answer:

$sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}$

Step-by-step explanation:

given is the Differential equation in I order linear as

$y′+4y=48t,y(0)=9.$

Take Laplace on both sides

$L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}$

Now if we take inverse we get y(t) the solution

Thus the algebraic equation would be $sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}$

8 0

2 years ago

According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most

AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 186, \pi = 0.11$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155$

His 95% confidence interval is (0.065, 0.155).

4 0

2 years ago

In a café, drinks are priced according to what size they are.

Andrei [34K]

A) Gavin’s drinks altogether cost £9.00
1.50+2.50x3
=1.50+7.50
=£9.00
b) Lian gets back £3.50
1.50+2.00+3.00
=6.50

10.00-6.50=£3.50

8 0

2 years ago