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Luda [366]
1 year ago
14

The ice skating rink charges an hourly fee for skating and 3$ to rent skates for the day. Gillian rented skates and skated for 2

hours and was charged $21. Which equation represents the cost c(x) of ice skating as a function of x the number of hours of skating
A. C(x)=3x+3
B. C(x)=6x+3
C. C(x)=7x+3
D. C(x)=8x+3
Mathematics
2 answers:
o-na [289]1 year ago
8 0
It starts with a $3 dollar charge. If he was charged 21, that means that 18 of those dollars were from the time he spent there. That means that it is $9 per hour and none of the answers upthere are correct

It should be c(x)=9(x)+3
Guest
1 year ago
There ain't no 9 in it.
Guest
1 year ago
oop get called out
Debora [2.8K]1 year ago
5 0

Answer:

Its B= C(x)=6x+3

Step-by-step explanation:

21 - 3 is 18

If gillian skated for three hours, then each hour is six dollars.

if x equals the number of hours then we would plug in 3 for x

C(x)= ?(3) + ?

each hour is six dollars so we plug in 6 right next to x

C(x)= 6(3) + ?

The total price is 18 plus 3 because he borrowed the skates so our final answer is 21 dollars

C(x)=6x+3

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Paula has a dog that weighs 3 times as much as Carla's dog
ivanzaharov [21]

Answer:

The weight of Paula's dog is 36 pounds.

Step-by-step explanation:

SO we would draw one box for the weight of Carla's dog. Then we would draw 3 boxes for the weight of Paula's dog.

To find how much does Paula's dog weigh we divide the total weight of the dogs by the total number of boxes.

So then you would calculate 48 divided by 4.

The weight of Carla's dog is 12 pounds.

Therefore the weight of Paula's dog is 3x12=3x10+3x2=30+6=36 pounds.

4 0
1 year ago
What value of n makes the equation true? -1/5n + 7 =2
klasskru [66]
The answer is 25.
-1/5n = -5
-n = -25
n = 25
7 0
1 year ago
Read 2 more answers
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
2 years ago
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zimovet [89]

Answer:

Yes it does

Step-by-step explanation:

We can use two sample t-test to draw the conclusuion. However, by looking at the information of mileage of tyres on asphalt and concrete-paved highways, we can say that since mean milege of tyres on concrete is lesser, tyres wear faster on concrete-paved highways.

4 0
1 year ago
Question 1: Classify the system of equations and identify the number of solutions. 3 = 4x + y 2y = 6 − 8x Answers: inconsistent;
Mariana [72]

Answer:

1st: consistent and dependent

2nd: (-2,0). Simply put the called and check.

7 0
1 year ago
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