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2 years ago

Two pence coins are used to make a square. If one millioncoins were used, what would be the length of the sides of the square?

Mathematics

1 answer:

Slav-nsk [51]2 years ago

7 0

Answer:

i dont know the answer

Step-by-step explanation:

just put a random answer and hope for the best

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Edgar ran eee meters per second, and Mathieu ran mmm meters per second. The boys ran for ttt seconds.

Oksana_A [137]

Answer:

The expression showing how many more meters Mathieu ran than Edgar ran during that time is $t(m-e)$ .

Step-by-step explanation:

Edgar ran 'e' meters per second, and Mathieu ran 'm' meters per second. The boys ran for 't' seconds.

The expression $t(m-e)$ describes how many more meters Mathieu ran than Edgar ran during that time.

We can also use the expression $tm-te$ represent the same quantity.

We know that,

$\text{Distance} =\text{Speed}\times \text{Time}$

Distance covered by Edgar = te

Distance covered by Mathieu = tm

Difference in distance $d= tm - te=t(m-e)$

The expression showing how many more meters Mathieu ran than Edgar ran during that time is $t(m-e)$ .

7 0

1 year ago

Read 2 more answers

Keenan currently does a total of 888 pushups each day. He plans to increase the number of pushups he does each day by 222 pushup

marishachu [46]

Answer:

8 + 2x = 30

Step-by-step explanation:

Given,

The initial number of push-ups he does in each day = 8,

And, the number of push-ups, he increases per day = 2,

Let x be the number of days after he will reach his target of 30 push-ups,

Since, the number of push-ups she will increase in x days = 2x,

Thus, the number of push-ups she will do after x days = 8 + 2x,

⇒ 8 + 2x = 30, which is the required equation.

4 0

1 year ago

Thomas purchased a bag of marbles on Monday. On Tuesday he gave half of the marbles to his brother. On Wednesday he gave eight m

kupik [55]

Answer:

168

Step-by-step explanation:

60+16+8 is 84

84 times 2 is 168

Mark me as brainliest if this helps!

6 0

1 year ago

PLSS HELPPP 20 POINTS

Maurinko [17]

Answer:

Step-by-step explanation:

just did it

7 0

1 year ago

Read 2 more answers

Find the point (x,y) of x2+14xy+49y2=100 that is closest to the origin and lies in the first quadrant.

Gala2k [10]

Notice that

$x^2+14xy+49y^2=(x+7y)^2$

so the constraint is a set of two lines,

$(x+7y)^2=100\implies\begin{cases}x+7y=10\\x+7y=10\end{cases}$

and only the first line passes through the first quadrant.

The distance between any point $(x,y)$ in the plane is $\sqrt{x^2+y^2}$ , but we know that $\sqrt{f(x,y)}$ and $f(x,y)$ share the same critical points, so we need only worry about minimizing $x^2+y^2$ . The Lagrangian for this problem is then

$L(x,y,\lambda)=x^2+y^2+\lambda(x+7y-10)$

with partial derivatives (set equal to 0)

$L_x=2x+\lambda=0$

$L_y=2y+7\lambda=0$

$L_\lambda=x+7y-10=0$

We have

$L_y-7L_x=2y-14x=0\implies y=7x$

which tells us that

$x+7y-10=0\iff x+49x=10\implies x=\dfrac15\implies y=\dfrac75$

so that $\left(\dfrac15,\dfrac75\right)$ is a critical point. The Hessian for the target function $x^2+y^2$ is

$H(x,y)=\begin{bmatrix}2&0\\0&2\end{bmatrix}$

which is positive definite for all $x,y$ , so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is $\sqrt{\left(\dfrac15\right)^2+\left(\dfrac75\right)^2}=2$ .

3 0

2 years ago