Answer:
The longest day of the year is day 172
Step-by-step explanation:
Since the length of day is L(t)=727+22sin[2π(t−80.75)/365], the maximum length of day is obtained when sin[2π(t−80.75)/365] is at its maximum value which is 1. So. sin[2π(t−80.75)/365] = 1
We now solve this to find the day at which this maximum value occurs.
sin[2π(t−80.75)/365] = 1
[2π(t−80.75)/365] = sin⁻¹(1)
[2π(t−80.75)/365] = π/2
dividing both sides by 2π/365, we have
[2π(t−80.75)/365] ÷ 2π/365 = π/2 ÷ 2π/365
t−80.75 = 365/4
t−80.75 = 91.25
t = 91.25 + 80.75
t = 172
The longest day of the year is day 172
The answer is 24m^2 i just finished that test and that was the answer.<span />
Number of toothpicks required per student = At least 9
Total number of students = 30
Number of toothpicks required for the entire class = At least 9 × 30 = At least 270
Number of toothpicks in the bag in the class storage room = 50
Additional number of toothpicks required to be bought to make sure there are enough toothpicks = 270 - 50 = 220
Hence, she needs to buy 220 toothpicks.
Given parameters:
Bearing of the tree from the house = 295°
Unknown:
Bearing of the house from the tree = ?
Solution:
This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.
To find the back bearing in this regard, simple deduct the forward bearing from 360°;
Backward bearing = 360° -295°
= 65°
The bearing from house to the tree is 65°
