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JulijaS [17]
2 years ago
6

Point F is on line segment EG given EG=5x + 7, EF=5x, and FG=2x - 7, determine the numerical length of FG

Mathematics
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

FG = 7

Step-by-step explanation:

Given

EG = 5x + 7

EF = 5x

FG = 2x - 7

Required

Determine the length of FG

Since, F is on segment EG, then

EG= EF + FG

Substitute values for EG, EF and FG

5x + 7 = 5x + 2x - 7

Collect Like Terms

5x - 5x - 2x = -7 - 7

- 2x = -14

Solve for x

x = -14/-2

x = 7

Substitute 7 for x in FG = 2x - 7

FG = 2 * 7- 7

FG = 14- 7

FG = 7

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The graphs of the quadratic functions f(x) = 6 – 10x2 and g(x) = 8 – (x – 2)2 are provided below. Observe there are TWO lines si
natta225 [31]

Answer:

a) y = 7.74*x + 7.5

b)  y = 1.148*x + 6.036

Step-by-step explanation:

Given:

                                  f(x) = 6 - 10*x^2

                                  g(x) = 8 - (x-2)^2

Find:

(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation

(b) The other line simultaneously tangent to both graphs has equation,

Solution:

- Find the derivatives of the two functions given:

                                f'(x) = -20*x

                                g'(x) = -2*(x-2)

- Since, the derivative of both function depends on the x coordinate. We will choose a point x_o which is common for both the functions f(x) and g(x). Point: ( x_o , g(x_o)) Hence,

                                g'(x_o) = -2*(x_o -2)

- Now compute the gradient of a line tangent to both graphs at point (x_o , g(x_o) ) on g(x) graph and point ( x , f(x) ) on function f(x):

                                m = (g(x_o) - f(x)) / (x_o - x)

                                m = (8 - (x_o-2)^2 - 6 + 10*x^2) / (x_o - x)

                                m = (8 - (x_o^2 - 4*x_o + 4) - 6 + 10*x^2)/(x_o - x)

                                m = ( 8 - x_o^2 + 4*x_o -4 -6 +10*x^2) /(x_o - x)

                                m = ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x)

- Now the gradient of the line computed from a point on each graph m must be equal to the derivatives computed earlier for each function:

                                m = f'(x) = g'(x_o)

- We will develop the first expression:

                                m = f'(x)

                                ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

Eq 1.                          (-2 - x_o^2 + 4*x_o + 10*x^2) = -20*x*x_o + 20*x^2

And,

                              m = g'(x_o)

                              ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

                              -2 - x_o^2 + 4*x_o + 10*x^2 = -2(x_o - 2)(x_o - x)

Eq 2                       -2 - x_o^2 + 4*x_o+ 10*x^2 = -2(x_o^2 - x_o*(x + 2) + 2*x)

- Now subtract the two equations (Eq 1 - Eq 2):

                              -20*x*x_o + 20*x^2 + 2*x_o^2 - 2*x_o*(x + 2) + 4*x = 0

                              -22*x*x_o + 20*x^2 + 2*x_o^2 - 4*x_o + 4*x = 0

- Form factors:       20*x^2 - 20*x*x_o - 2*x*x_o + 2*x_o^2 - 4*x_o + 4*x = 0

                              20*x*(x - x_o) - 2*x_o*(x - x_o) + 4*(x - x_o) = 0

                               (x - x_o)(20*x - 2*x_o + 4) = 0  

                               x = x_o   ,     x_o = 10x + 2    

- For x_o = 10x + 2  ,

                               (g(10*x + 2) - f(x))/(10*x + 2 - x) = -20*x

                                (8 - 100*x^2 - 6 + 10*x^2)/(9*x + 2) = -20*x

                                (-90*x^2 + 2) = -180*x^2 - 40*x

                                90*x^2 + 40*x + 2 = 0  

- Solve the quadratic equation above:

                                 x = -0.0574, -0.387      

- Largest slope is at x = -0.387 where equation of line is:

                                  y - 4.502 = -20*(-0.387)*(x + 0.387)

                                  y = 7.74*x + 7.5          

- Other tangent line:

                                  y - 5.97 = 1.148*(x + 0.0574)

                                  y = 1.148*x + 6.036

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1 year ago
If y = 3x and 2x – 4y = 3, then x=
lozanna [386]

Answer:

x = -0.3

Step-by-step explanation:

You can substitute y in 2x – 4y = 3, to solve for x.

How to solve for x:

2x - 4(3x) = 3 (Simplify)

2x - 12x = 3 (Simplify)

-10x = 3 (Divide by -10)

x = -0.3

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2 years ago
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A council reviews the number of bedrooms in 40 houses located in the same area. The table shows the information gathered.
Liono4ka [1.6K]

Answer:

a) 15 house with 3 bedrooms

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Step-by-step explanation:

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1 year ago
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Four brothers each bought two hotdogs and a bag of chips at the concession stand.if the bag of chips was $1.25,and the total was
ahrayia [7]

Answer:

  $1.65

Step-by-step explanation:

The total purchase can be described by ...

  4(2h +1.25) = 18.20 . . . . where h is the price of a hot dog

  8h = 13.20 . . . . . . . . . . . subtract 5.00

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1 year ago
In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the
IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = \frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100

Percentile of 86 = \frac{176}{400} \times 100

Since, we cancelled 400 with 100 we get 4 , hence above expression becomes,

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So, percentile of 86 = 49

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