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JulijaS [17]
2 years ago
6

Point F is on line segment EG given EG=5x + 7, EF=5x, and FG=2x - 7, determine the numerical length of FG

Mathematics
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

FG = 7

Step-by-step explanation:

Given

EG = 5x + 7

EF = 5x

FG = 2x - 7

Required

Determine the length of FG

Since, F is on segment EG, then

EG= EF + FG

Substitute values for EG, EF and FG

5x + 7 = 5x + 2x - 7

Collect Like Terms

5x - 5x - 2x = -7 - 7

- 2x = -14

Solve for x

x = -14/-2

x = 7

Substitute 7 for x in FG = 2x - 7

FG = 2 * 7- 7

FG = 14- 7

FG = 7

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tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
2 years ago
Coach De Leon purchases sports equipment. Basketballs cost $20.00 each, and soccer balls cost $18.00 each. He had a budget of $1
zepelin [54]

Answer:

18s+20b<_150

Step-by-step explanation:

He can buy 5 basketballs and 2 soccer balls. This equation is correct because 18x2 is 36 and 20x5 is 100. So that will be a total of $100. This makes the equation 100<_150. You can infer that this equation is true.

8 0
1 year ago
An employment agency requires applicants average at least 70% on a battery of four job skills tests. If an applicant scored 70%,
brilliants [131]

Answer:

atleast 52

Step-by-step explanation:

Given that an employment agency requires applicants average at least 70% on a battery of four job skills tests.

An applicant scored 70%, 77%, and 81% on the first three exams,

Since weightages are not given we can assume all exams have equal weights

Let x be the score on the 4th test

Then total of all 4 exams = 70+77+81+x\\= 228+x

Average should exceed 70%

i.e.\bar X \geq 70\\Total\geq 70(4) =280

Comparing the two totals we have

228+x\geq 280\\x\geq 280-228 = 52

Hemust  score on the fourth test a score atleast 52 to maintain a 70% or better average.

3 0
2 years ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3\frac{1}4 mi, charges = $4.40

So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of 3\frac{1}8 miles lies within the range 3 mi - 3\frac{1}4 mi.

So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

6 0
2 years ago
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What is it comparing it to?

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7 0
2 years ago
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