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Fantom [35]
2 years ago
9

3(2x+4)=2(4x-1) please help this is algebra 2

Mathematics
1 answer:
SashulF [63]2 years ago
7 0
3(2x+4)= 2(4x-1)
6x+12=8x-2
6x-8x= -2-12
-2x=-14

X= 7

Solve for X by simplifying both sides of the equation, then isolating the variable.
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Javier writes an integer on a piece of paper. The absolute value of his number is less than 4. Which is true of the possible val
ANTONII [103]
<span>The possible values are less than 4 but greater than –4.</span>
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2 years ago
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The results of a race car are shown. Determine who drove the fastest. Explain.
monitta

We have to calculate speed for 1 lap for all of 'em.

Cutwright - 84/35 = 2.4 mins for 1 lap

Evans- 96.6/42 = 2.3 mins for 1 lap

Liza- 102.6/38 = 2.7 mins for 1 lap

 So, EVANS drove fastest among them as he took less time...

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2 years ago
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I rent a gym for $150.00 for 30 students. Another time I rent the gym for $270.00 for 70 students. I need to find a fixed rate.
masha68 [24]

Answer: y = 3x + 60

<u>Step-by-step explanation:</u>

Set up two equations and solve the system:

 270 = 70x + b

- <u>(150 = 30x + b)</u>

  120 = 40x

    3   =  x

Input "x" into one of the equations and solve for "b":

150 = 30x + b

150 = 30(3) + b

150 = 90 + b

60 = b


Equation: y = 3x + 60

This means that there is a flat fee of $60 plus a rate of $3 per student


5 0
2 years ago
I have a hat that contains six nickels and five pennies. I draw coins from the hat at random, without replacement. Find the prob
Rzqust [24]
6 nickels and 3 pennies
8 0
1 year ago
A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na
Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

v=\frac{d}{t}

where d is the total distance traveled and t is the total time needed.

d=\frac{4.00}{1.75}=2.29 km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0
1 year ago
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