All categories

2 years ago

3(2x+4)=2(4x-1) please help this is algebra 2

1 answer:

7 0

3(2x+4)= 2(4x-1)
6x+12=8x-2
6x-8x= -2-12
-2x=-14

X= 7

Solve for X by simplifying both sides of the equation, then isolating the variable.

You might be interested in

Catherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tub

kakasveta [241]

Answer:

4. 54- 8.5x>20

Step-by-step explanation:

Catherine only has $54, so she cannot spend more than that.

The canvas will cost at least $20, but we don't know how much exactly.

The tubes cost $8.50 each.

So, she starts with a total budget of $54, out of which she will buy paints (8.5x) and she wants to have at least $20 left for canvas.

So, we transpose those facts into the inequity:

54 - 8.5x > 20

8 0

2 years ago

Read 2 more answers

What is the completely factored form of p4 - 16?

il63 [147K]

The completely factored form of p^4-16 is:

$(p^2+4)(p+2)(p-2)$

Step-by-step explanation:

We have to factorize the given expression to get the final result

Given

$p^4-16\\Using\ Formula: a^2-b^2=(a+b)(a-b)\\(p^2)^2-(4)^2\\=(p^2+4)(p^2-4)$

p^2-4 can further be factored again

$=(p^2+4)[(p)^2-(2)^2]\\=(p^2+4)(p+2)(p-2)$

The completely factored form of p^4-16 is:

$(p^2+4)(p+2)(p-2)$

Keywords: Factorization

Learn more about factorization at:

#LearnwithBrainly

8 0

2 years ago

What is the approximate perimeter of the figure?

exis [7]

<span>This is a perimeter of 1/4 of a circle. We know that the radius of the circle: r = 5 in. Also the perimeter of the circle is : 2 * r * Pi = 2 * 5 * 3.14 = 31.4 in. For the quarter of a circle it its 31.4 : 4 = 7.85 in. After that we can add the 2 lengths of the radius: P = 5 + 5 + 7.85 = 17.85 in ( approx. 17.9 in ). Answer: C ) 17.9 in. </span>

7 0

2 years ago

Economists study the way society uses its resources. One important resource studied is agriculture. The recent increase in deman

Anon25 [30]

Answer:

Which is a reason that organic farming is more expensive than conventional farming?

Organic farmers must pay for a costly certification process

How many years must a farm be run organically before its produce can be labeled as “organic”?

What is a benefit of crop rotation?

Rotating crops can help build healthy soil.

Step-by-step explanation:

Just took the test!

8 0

2 years ago

Read 2 more answers

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

2 years ago