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2 years ago

Which composition of transformations maps figure RSTUV to figure R"S"T"U"V"?

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

5 0

Answer:

option: B is correct

A reflection across line n followed by a 270° rotation about point P.

Step-by-step explanation:

Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".

Hence, option B is correct.

( A reflection across line n followed by a 270° rotation about point P )

Nostrana [21]2 years ago

4 0

<h2>Answer:</h2>

The correct answer is option B.

A reflection across line n followed by a 270° rotation about point P.

Step-by-step explanation:

In the attached figure, we can see that RSTUV has been reflected down in a straight path across line 'n' to make R'S'T'U'V'.

After this transformation, the figure is again rotated across point P. This rotation is 270 degrees. Now we obtain the figure R"S"T"U"V".

Therefore, option B is correct.

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2) Multiply the purchase by that decimal

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2 years ago

A nutritionist attempts to determine an association between where food is prepared and the number of calories the food contains.

Oksi-84 [34.3K]

Given the conditional relative frequency table below which was generated by column using frequency table data comparing the number of calories in a meal to whether the meal was prepared at home or at a restaurant.

Number of Calories and Location of Meal Preparation.
Home Restaurant Total
≥ 500 calories 0.15 0.55 0.28

< 500 calories 0.85 0.45 0.72

Total 1.0 1.0 1.0

To determine whether there is an association between where food is prepared and the number of carories the food contain, we recall that an "association" exists between two categorical variables if the column conditional relative frequencies are different for the columns of the table. The bigger the differences in the conditional relative frequencies, the stronger the association between the variables. If the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables. Such variables are said to be independent.

For the given conditional relative freduency, we can see that there is a significant difference between the columns of the table.
i.e. 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

Therefore, we can conclude from the given answer options that there is an association because the value 0.15 is not similar to the value 0.55

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2 years ago

How do you simplify 77.28/9.2

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The answer is 8.4 all you do is divide them together to get your answer.

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2 years ago

The hospital shop buys cereal bars in boxes of 4.

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First, you divide 58 bars by 4. The answer will be 14 boxes with 2 bars remaining in the box.

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2 years ago

The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of X is N (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

Step-by-step explanation:

The random variable X is defined as the amount of sodium consumed.

The random variable X has an average value of, μ = 9.8 grams.

The standard deviation of X is, σ = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable X follows a normal distribution with parameters μ = 9.8 grams and σ = 0.8 grams.

Thus, the distribution of X is N (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (X) to z-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of z as follows:

$P(-z$

The value of z for P (Z < z) = 0.65 is 0.39.

Compute the value of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

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2 years ago