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Sergio [31]
2 years ago
13

Which functions represent a piece of the function? Select three options.

Mathematics
2 answers:
uysha [10]2 years ago
7 0

Answer:

Step-by-step explanation:

Help

kirill115 [55]2 years ago
4 0

Answer:

are possible awnsers

Step-by-step explanation:

a b and e

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For what natural values of n is the difference (2−2n)−(5n−27) positive?
pashok25 [27]

(2−2n)−(5n−27) >0

distribute

2-2n -5n +27 >0

combine like terms

-7n +29 >0

subtract 29 from each side

-7n> -29

divide by -7  (flips the inequality)

n < -29/-7

n <4.14

natural numbers are 1,2,3,4......

n must be 1,2,3,4

Answer: 1,2,3,4

4 0
2 years ago
Read 2 more answers
What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)
Pachacha [2.7K]

Answer:

The third option listed: \sqrt[3]{2x} -6\sqrt[3]{x}\\

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

7\sqrt[3]{2x}  -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x}  -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x}  -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

7\sqrt[3]{2x}  -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}

Therefore this is the simplified radical expression: \sqrt[3]{2x} -6\sqrt[3]{x}\\

5 0
2 years ago
Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br
olga2289 [7]
Since F=m•a, you want to show that a = -5.5

5 0
1 year ago
Read 2 more answers
What is 8290/21 with an remainder
Lerok [7]
The remainder is 8290
8 0
1 year ago
Let p, q, and r be the propositions p: You get an A on the final exam. q: You do every exercise in this book. r: You get an A in
babunello [35]

Answer:

a) r ^ ¬q

b) p ^ꓥqꓥ^ r

c) r → p

d) p ^ ¬qꓥ^ r

e) (p ^ q) → r

f) r ↔ (q v p)

Step-by-step explanation:

 

 

ꓥ^ = AND Conjunction

vꓦ = OR disjunction

¬ = NOT Negation

↔ = Double Implication

→ = implication

6 0
1 year ago
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