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melisa1 [442]
2 years ago
10

An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near

est tenth of an inch?

Mathematics
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

The height of the triangle is 5.2 inches

Step-by-step explanation:

we know that

An <u>equiangular triangle</u> is a triangle where all three interior angles are equal in measure

Remember that an equilateral triangle has three equal sides and three equal interior angles

so

An equiangular triangle Is the same that an equilateral triangle. The measure of its interior angles is equal to 60 degrees

Let

h ----> the height of triangle

b ---> the length side of the triangle

Applying Pythagoras Theorem

h^2=b^2-(b/2)^2

we have

b=6\ in

substitute

h^2=6^2-(6/2)^2

h^2=36-9

h^2=27

h=\sqrt{27}\ in

h=5.2\ in

see the attached figure to better understand the problem

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A multi-layer cake is in the shape of a right cylinder. The height of the cake is 20 centimeters, and its radius is 10 cm. If ea
gizmo_the_mogwai [7]

Answer:

There are total 5 layers.

Step-by-step explanation:

A multi-layer cake is in the shape of a right cylinder.

Height of the cake is = 20 cm

Radius is = 10 cm

Each of the cake layers has a volume of approximately 1,250 cm³.

Means, the volume of 1 cylindrical layer is 1250 cubic cm with radius as 10 cm and we have to find the height.

Volume of the cylinder is given as:

V=\pi r^{2} h

1250=3.14\times(10)^{2}\times h

1250=314 h

h=\frac{1250}{314}

h = 3.98 or approximately height of 1 layer is 4 cm.

As the cake's height is 20 cm so, there are \frac{20}{4}=5 layers in the cake.

Answer: There are 5 layers in the cake.

5 0
2 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
2 years ago
Jamal works in a city and sometimes takes a taxi to work. The taxicabs charge $1.50 for the first 1/5 mile and $0.25 for each ad
Natalija [7]
1.50+.25x=3.75
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x=9
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4 0
2 years ago
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a small table is 2 feet by 3 feet a large table is twice as long and rwice as wide as the small table. Whats the area of the lar
Scorpion4ik [409]

Answer:

The area of larger table is 24 square feet.

Step-by-step explanation:

Given are the length and width of small table

l_s = 2\ ft\\w_s = 3\ ft

The area of a rectangular table is calculated by multiplying the length and width. It is also given that the length and width of the larger table is double the length and width of small table

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l_l = 2*2 = 4\ feet\\w_l = 3*2 = 6\ feet

The area of larger table will be:

A_l = l_l*w_l\\= 4 * 6\\=24\ ft^2

Hence,

The area of larger table is 24 square feet.

7 0
1 year ago
On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.
kirill115 [55]
B or C  hope its helps...

 

5 0
2 years ago
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