When the ball will hit the ground, the height will be zero. So we need to replace

with 0 in our equation, and solve for

:


To solve this equation we are going to use the quadratic formula:

.
From our height equation, we can infer that

,

, and

. So lets replace those values in our quadratic formula to find



or


or

Since time cannot be negative,

is the solution of our equation.
We can conclude that the ball will hit the ground after
2.71 seconds.
Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task:
![\sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} = \sqrt[1/ 9 ]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%0A%0A%3D%20%20%20%5Csqrt%5B1%2F%209%20%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20)
Now we can simplify:
![\sqrt[1/9]{x} + 1/9+1/9+1/9 = x^{4/9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2B%201%2F9%2B1%2F9%2B1%2F9%0A%0A%3D%20x%5E%7B4%2F9%7D%20)
So the answer is <span>
C:x to the four ninths power</span>
Answer:
2 x minus y = negative 6 and 3 x minus y = negative 5
Step-by-step explanation:
y = 2(x+3) = 2x + 6 or 2x - y = -6
y = 5 + 3x or 3x - y = -5
Write and solve an equation of ratios:
900 students 45 teachers
------------------ = -----------------
x 110 teachers
Cross multiplying, we get (900)(110) / 45, or
so x = # of students in the high school = 2200 (answer)