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Hoochie [10]
2 years ago
5

Profit is the difference between revenue and cost. The revenue, in dollars, of a company that manufactures televisions can be mo

deled by the polynomial 3x2 + 180x. The cost, in dollars, of producing the televisions can be modeled by 3x2 – 160x + 300. The variable x is the number of televisions sold.
If 150 televisions are sold, what is the profit?
Mathematics
2 answers:
-Dominant- [34]2 years ago
7 0

Answer:

The answer is C. - $50,700

Step-by-step explanation:

Doss [256]2 years ago
3 0

\bf \stackrel{\mathbb{P~R~O~F~I~T}}{\stackrel{Revenue}{(3x^2+180x)}~~~~-~~~~\stackrel{Costs}{(3x^2-160x+300)}}\implies 20x+300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{profit equation}}{P(x)=20x+300}\implies \stackrel{\textit{150 televisions sold, x = 150}}{P(150)=20(150)+300}\implies P(150)=3300

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Test the given claim. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, and then state the concl
never [62]

Answer:

a) Failed to reject the null hypothesis (P-value=0.09).

b) The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

Step-by-step explanation:

a) We have to perform a hypothesis test for the difference of proportions.

The null and alternative hypothesis are:

H_0: \pi_1\geq\pi_2\\\\H_1: \pi_1

The significance level is 0.05.

The proportion of the passenger cars owners is:

p_1=\frac{239}{2142} =0.1116

The proportion of commercial truck owners is:

p_2=\frac{54}{399}=0.1353

The weigthed average p is

p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{239+54}{2142+399}=0.1153

The estimated standard deviation is

s=\sqrt{\frac{p(1-p)}{n_1}+\frac{p(1-p)}{n_2}} =\sqrt{\frac{0.1153(1-0.1153)}{2142}+\frac{0.1153(1-0.1153)}{399}} =0.0174

We can calculate the z-value as:

z=\frac{\Delta p}{s}=\frac{0.1116-0.1353}{0.0174}=-1.362

The P-value for z=-1.362 is P=0.0866.

The P-value (0.09) is greater than the significance level (0.05), so it failed to reject the null hypothesis. There is no enough evidence to prove that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

b) We can construct a 95% CI, according to the significance level of 0.05.

The z-value for this CI is 1.96.

We have to recalculate the standard deviation:

\sigma=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2}} =\sqrt{\frac{0.1116(1-0.1116)}{2142} +\frac{0.1353(1-0.1353)}{399}} =0.0184

The lower limit is then:

LL=(p_1-p_2)-z*\sigma=(0.1116-0.1353)-1.96*0.0184=-0.0238-0.0361\\\\LL=-0.0599

The upper limit is:

UL=(p_1-p_2)+z*\sigma=(0.1116-0.1353)+1.96*0.0184=-0.0238+0.0361\\\\UL=0.0124

The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

In this case, we can conclude that the difference between the proportions, with 95% confidence, can still be equal or greater than zero, meaning that it is possible passenger car owners violate laws more than truck owners.

7 0
2 years ago
By visual inspection determine the best-fitting regression model for the data plot below
Pie

Answer:

Exponential

Step-by-step explanation:

By visual inspection the graph generated by the points plotted is an exponential graph as the graph curves upward. The graph is also continous and differs from either a decreasing or increasing Linear graph, which shows a straight best of fit pattern. Hence, the graph most closely represents an exponential graph from visual examination.

8 0
2 years ago
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An angle measuring (525n)° is in standard position. For which value of n will the terminal side fall along the negative portion
Mazyrski [523]

For n=2,

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3150° angle takes 8 complete revolution and then makes an angle of 270° which will fall along negative y-axis.



8 0
2 years ago
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Stels [109]
The first thing we must do for this case is to find the equation of the line.
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y = (1/2) x - 4
 
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The slope is 1/2
 
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7 0
2 years ago
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Allie works for Canton Water Works. Her annual salary is $75,964.
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I think it’s gonna be B
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