His equation could be written in quadratic form, which is ax^2+bx=c
Answer:
<h2>
17.6ft²</h2>
Step-by-step explanation:
The formula for calculating the surface area of a triangular prism is expressed as shown below:
SA= bh + pH
b= base of the triangle
h- height of the triangle
p= perimeter of the triangle
H= height of the prism
Given b = 1foot
h = 2feet
perimeter of the triangle = sum of all its sides = 1ft + 2ft + 2.2ft
p = 5.2ft
H = 3ft
Substituting the values into the formula for finding the surface area:
SA = 1(2)+5.2(3)
SA = 2+15.6
SA = 17.6ft²
The surface area of the triangular prism is 17.6ft²
Answer:
m∠FJH=60°
Step-by-step explanation:
The complete question is
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°
What is FJH
we know that
m∠FJH=m∠FJG+m∠GJH -----> equation A
If ray JG is an angle bisector of ∠FJH
then
m∠FJG=m∠GJH -----> equation B
substitute the given values in equation B and solve for x
(2x + 4)°=(3x -9)°
3x-2x=4+9
x=13
Find the measure of angle FJH
m∠FJH=(2x + 4)°+(3x -9)°
substitute the value of x
m∠FJH=(2(13) + 4)°+(3(13) -9)°
m∠FJH=(30)°+(30)°
m∠FJH=60°
ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:

Substitute:
