Hillary rolls 2 number cubes numbered 1 through 6 while playing her favorite board game. She will get a second turn if she rolls
2 answers:
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<span>
it consists of a rectangle, dimensions L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2
</span>then, you have one half of the area of the circle that has diameter R = 3ft - radius will be r = 1.5ft the area of that half will be:
Ac = r^2
/ 2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2
= 7.065 ft^2/ 2
= 3.5325ft^2
A = Ar + Ac
A = 12ft^2 + 3.5325ft^2
A = 15.5325ft^2
<span>At the rate of $2 per square foot, the cost will be:
$ 15.5325*2 = 31.07 </span>
<span>
it consists of a rectangle, dimensions L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2
</span>then, you have one half of the area of the circle that has diameter R = 3ft - radius will be r = 1.5ft the area of that half will be:
Ac = r^2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2
= 7.065 ft^2/ 2
= 3.5325ft^2
A = Ar + Ac
A = 12ft^2 + 3.5325ft^2
A = 15.5325ft^2
<span>At the rate of $2 per square foot, the cost will be:
$ 15.5325*2 = 31.07 </span>
Total customers are = 360
Number of polled people who purchased ice cream = 260
Number of polled people who purchased both ice cream and yogurt = 250
Hence, people who purchased only ice cream are=
And are people who purchased yogurt.
So, people who purchased yogurt only =
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.