Answer:
The Watermelon candies cost 13 more cents then the chocolate.
Step-by-step explanation:
$3.48 divided by 12 is 29 cents
$1.28 divided by 8 is 16 cents
Subtract 16 from 29 and get 13
The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>
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Answer: The two answers are 1.08<em>T</em> and (1 + 
)<em>T</em>.
Step-by-step explanation:
Try multiplying 1.08 times any random number. If you use 5, 1.08 times 5 gives you 5.4. This makes sense. Solve the other other expression as well and substitute <em>T</em><em> </em> with the SAME number that you used before (5). Hope that helps!
I could work out this question but not exactly sure because I think that you need to find out how many kal has because kal is the problem here. once u figure that out. times the number by 12 and yeah. that would be your answer but idk how many kal has.
In the general case in Cartesian coordinates, you would use the definition of a parabola as the locus of points equidistant from the focus and directrix. The equation would equate the square of the distance from a general point (x, y) to the focus with the square of the distance from that point to the directrix line.
Suppose the focus is located at (h, k) and the equation of the directrix is ax+by+c=0. The expression for the square of the distance from (x, y) to the point (h, k) is ...
(d₁)² = (x-h)²+(y-k)²
The expression for the square of the distance from (x, y) to the directrix line is
(d₂)² = (ax+by+c)²/(a²+b²)
Equating these expressions gives the equation of the parabola.
(x-h)²+(y-k)² = (ax+by+c)²/(a²+b²)
When the directrix is parallel with one of the axes, one of the coefficents "a" or "b" is zero and the equation becomes much simpler. Often, it would be easier to make use of the formula (for a directrix parallel to the x-axis):
y = 1/(4p)*(x -h)² +k
where the (h, k) here is the vertex, the point halfway between the focus and directrix, and "p" is the (signed) distance from the focus to the vertex. (p is positive when the focus is above or to the right of the vertex.)
