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sergeinik [125]
2 years ago
12

Two cards are drawn one at a time from a full deck of cards. a) What’s the probability they are an ace or a heart? b) What’s the

probability they are neither ace nor a heart?
Mathematics
1 answer:
nika2105 [10]2 years ago
3 0

Probability of ace drawn is: 4/52

Probability of heart drawn is: 13/52

For question (a)

P(ace or heart)=p(ace) + p(heart)

P(ace or heart)=4/52 + 13/52

P(ace or heart)=17/52

For question (b)

P(ace)' =1 - 4/52 = 48/52

P(heart) =1 - 13/52 = 39/52

P(neither ace nor heart) = 48/52 × 39/52

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Elena-2011 [213]

Answer:

36.00 pesos or $1.73

Step-by-step explanation:

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Chen completed the division problem below. 0.9 StartLongDivisionSymbol 192.6 EndLongDivisionSymbol right arrow 9 StartLongDivisi
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Answer:

He should have multiplied both numbers by 100

Step-by-step explanation:

Given

See Attachment for given

Required

What's Chen error

Chen error is at step 2 where he changed 0.9 to 9.

Any changes made on the divisor must also be made on the dividend

He got 9 by multiplying 0.9 by 10;

So, his mistake is that he should have multiplied both numbers by the same number.

From the list of given options, the option that best answer this question is He should have multiplied both numbers by 100

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2 years ago
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Based only on the information given in the diagram which congruence theorems or postulates could be givenas reasons why triangle
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The  answer is C, E, and F on Apex
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2 years ago
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Without using a calculator, what is 30% of 546? (You can round up to avoid decimal points)
madreJ [45]

Answer:

Hey there!

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5 0
2 years ago
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An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe
stealth61 [152]

Answer:

20,944 years

Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years.  We are given the k value of .00012.  If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon.  What's left then is 8.1%.  Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal.  We can use the 8.1.  Here's the formula:

N(t)=N_{0} e^{-kt}

where N(t) is the amount left over after the decay occurs, N_{0} is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years.  Filling in accordingly,

8.1=100e^{-.00012t}

Begin by dividing the 100 on both sides to get

.081=e^{-.00012t}

Now take the natural log of both sides.  Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

ln(.081)= -.00012t

Take the natual log of .081 on your calculator to get

-2.513306124 = -.00012t

Now divide both sides by -.00012 to get t = 20,944 years

4 0
2 years ago
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