Factor 16x2 + 121 over the set of complex numbers. Enter your answer in the box.
1 answer:
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The equation of a parabola with vertex at (h,k) is
y=a(x-h)²+k
vertex isi at (0,0)
y=a(x-0)²+0
y=a(x)²
y=ax²
find a
we see that one point is (14,-74)
x=14 and y=-74
-74=a(14²)
-74=196a
divide both sides by 196
-37/98=a
the equation is
y=a(x-h)²+k
vertex isi at (0,0)
y=a(x-0)²+0
y=a(x)²
y=ax²
find a
we see that one point is (14,-74)
x=14 and y=-74
-74=a(14²)
-74=196a
divide both sides by 196
-37/98=a
the equation is