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Vera_Pavlovna [14]
1 year ago
6

Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
Mathematics
1 answer:
Vladimir [108]1 year ago
5 0

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

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12

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5(0.04y-0.08) >3(0.2y-0.05-0.4y)
MAXImum [283]

0.08(y + -1) + 0.12y = 0.14 + -0.05(10)

Reorder the terms:

0.08(-1 + y) + 0.12y = 0.14 + -0.05(10)

(-1 * 0.08 + y * 0.08) + 0.12y = 0.14 + -0.05(10)

(-0.08 + 0.08y) + 0.12y = 0.14 + -0.05(10)

Combine like terms: 0.08y + 0.12y = 0.2y

-0.08 + 0.2y = 0.14 + -0.05(10)

Multiply -0.05 * 10

-0.08 + 0.2y = 0.14 + -0.5

Combine like terms: 0.14 + -0.5 = -0.36

-0.08 + 0.2y = -0.36

Solving

-0.08 + 0.2y = -0.36

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.08' to each side of the equation.

-0.08 + 0.08 + 0.2y = -0.36 + 0.08

Combine like terms: -0.08 + 0.08 = 0.00

0.00 + 0.2y = -0.36 + 0.08

0.2y = -0.36 + 0.08

Combine like terms: -0.36 + 0.08 = -0.28

0.2y = -0.28

Divide each side by '0.2'.

y = -1.4

Simplifying

y = -1.4

3 0
2 years ago
Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig
Serga [27]

Answer:

1.4in

Step-by-step explanation:

Length of Photo = 4in

Width of Photo = 3in

Unknown:

Value of X = ?

Solution:

Follow these steps:

  Area of a rectangle  = l x w

Since the photo is a rectangle; area of photo:

  Area of photo  = 4in x 3in = 12in²

For the area of the ad;

   Length of ad  = 4 + x

   Width of ad = 3 + x

Given that,

                  the area of the photo  = \frac{1}{2} area of ad

                           12in²  = \frac{1}{2} area of ad

                   Area of ad  = 24in²

Area of the ad;

             (4 + x) (3 + x)  = 24

               12 + 4x + 3x + x² = 24

                12 + 7x + x²  = 24

                       x² + 7x = 24 - 12

                       x² + 7x = 12

                     x² + 7x - 12  = 0

            Using the almighty formula where

     a  = 1, b = 7 and c = -12

          x  = \frac{-b (+/-) \sqrt{b^{2} } - 4ac}{2a}

     

          x = \frac{-7 + \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}   or \frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}

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x is 1.4in

4 0
1 year ago
Sue played four games of golf for these games her modal score was 98 and her mean score was 100 her range of score was 10 what w
earnstyle [38]

Answer : Remaining two observation becomes 97 and 107.

Explanation :

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As we know that ,

Range = Highest-Lowest

Let highest observation be x

Let lowest observation be y

So equation becomes x-y=10 ----equation 1

So, observation becomes

x,98,98,y

Now, we use the formula of mean i.e.

Mean = \frac{\text{Sum of observation}}{\text{N.of observaton}}

So, mean =\frac{x=98=98+y}{4}=400\\\frac{196+x+y}{4}=100\\x+y=400-196\\x-y=204

So our 2nd equation becomes

x+y=204

On using elimination method of system of linear equation on these two equation we get,

x=97

and

x+y=204\\y=204-x\\y=204-97\\y=107

Hence , remaining two observation becomes 97 and 107.

8 0
1 year ago
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