7. The ruler below has eleven marks and can be used to measure lengths

If FC IS RS 4430 and the BEP in unitsis 89, then contribution margin is ?

Umnica [9.8K]

Answer: RS 49.8

Step-by-step explanation:

Given the following :

Fixed cost = RS 4430

Break even point = 89 units

Recall:

Break even point in units = Fixed cost ÷ contribution margin

Therefore,

Contribution margin equals;

(Fixed cost ÷ break even point in units)

= 4430 / 89

= 49.775280

= RS 49.8

5 0

2 years ago

4abc + (-9abc) + 10d?

nasty-shy [4]

-5abc+10d will be the answer.

8 0

2 years ago

Read 2 more answers

"most humans find it easier to remember words, rather than numbers. if you tell someone to go to www.icann.org, they can probabl

AURORKA [14]

It brings up Google search results that point to websites with the same question. Browsers aren't made to support base 2 addresses, so it won't go to 192.0.32.7. This question directs the user to paste a string of text into a browser and explain what happens.

7 0

2 years ago

Claudia brought a 16-cup jug filled with water to the soccer game. She shared the water with her teammates. How can Claudia find

yKpoI14uk [10]

Answer:

Claudia could estimate the amount of water that her teammates drank by using this process:

1. Measure the amount that Claudia herself drank.

2. Subtract that from the amount of water that the jug was filled with before the soccer game.

3. Find the difference of that and the current amount of water.

Step-by-step explanation:

4 0

2 years ago

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

2 years ago