Question

Kim drove from Mathtown at (-2, 5) to Geometryville at (3, -1) to Algebra Springs at (-6, -5), and then back to Mathtown. Find the total distance Kim traveled to the nearest hundredth.

Answer 1

Answer:

Option (3)

Step-by-step explanation:

To solve this question we will use the formula,

Distance (d) between two points $(x_1,y_1)$ and $(x_2,y_2)$,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between Mathtown (-2, 5) to Geometryville (3, -1)

$d_1=\sqrt{(3+2)^2+(-1-5)^2}$

    $=\sqrt{25+36}$

    $=\sqrt{61}$

    $=7.81$

Distance between Geometryville (3, -1) and Algebra Springs (-6, -5)

$d_2=\sqrt{(3+6)^2+(-1+5)^2}$

    $=\sqrt{81+16}$

    $=\sqrt{97}$

    $=9.85$

Distance between Algebra Springs (-6, -5) and Mathtown (-2, 5)

$d_3=\sqrt{(6-2)^2+(5+5)^2}$

    $=\sqrt{16+100}$

    $=\sqrt{116}$

    $=10.77$

Now total distance traveled by Kim = $d_1+d_2+d_3$

                                                           = 7.81 + 9.85 + 10.77

                                                           = 28.43

Therefore, Option (3) will be the answer.