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solong [7]
2 years ago
9

Assume that the playbook contains 9 passing plays and 15 running plays. The coach randomly selects 8 plays from the playbook. Wh

at is the probability that the coach selects at least 2 passing plays and at least 3 running plays?
Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
4 0
<span>Answer = probability that he selects exactly 2,3,4 or 5 passing plays. prob that he selects exactly two passing plays = (8C2)*(9*8)* (15*14*13*12*11*10) /(26*28*.....19) where: 8C2 is the number of ways of choosing two slots out of 8 and prob that he selects first passing play = 9/26 prob that he select second passing play = 10/25 etc you can calculate the other three cases similarly and sum to obtain the answer.</span>
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Answer:

{ x | x ≥ 0 }

Step-by-step explanation:

Given,

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2 years ago
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aniked [119]

Answer:

B. 1/25

Step-by-step explanation:

This question asks us to find (-2), or f(x) when x is equal to -2.

We know that f(x)=5^x. We also know that we are trying to find f(-2). Therefore, we must substitute -2 in for x.

f(x)=5^x

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Negative exponents follow the rule:

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f(-2)= 1/5^2

Evaluate the exponent in the denominator.

5^2=5*5=25

f(-2)=1/25

f(-2) is equal to 1/25, therefore B is the correct answer.

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2 years ago
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Lyrx [107]
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