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Nana76 [90]
2 years ago
13

1. Dennis made a 500 km trip in five hours. For the first two hours, Dennis had an average speed of 150 km/h. For the last two h

ours, Dennis had an average speed of 100 km/h. Which of the following is true about Dennis' trip? (25 Points) Dennis must have maintained a constant velocity throughout his trip. Dennis must have maintained a constant speed throughout his trip. O Dennis must have stopped for an hour in the middle of this trip Wich statemeent correctly discribes the locaton and Dennis must have driven without stopping during his trip​
Mathematics
1 answer:
Sati [7]2 years ago
6 0

Answer:

The correct option is;

Dennis must have stopped for an hour in the middle of this trip

Step-by-step explanation:

The given parameters are;

The distance Dennis covered in 5 hours = 500 km

Dennis's average speed in the first two hours = 150 km/h

Dennis's average speed in the last two hours = 100 km/h

Therefore;

Dennis traveled 150 km/h × 2 h = 300 km in the first two hours

Dennis traveled 100 km/h × 2 h = 200 km in the last two hours

Which gives, Dennis traveled 300 km + 200 km in  2h + 2h = 4h

Therefore, Dennis traveled 500 km in 4 hours and Dennis must have stopped for an hour in the middle of this trip.

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Answer:

P(Bag is Defective) = 0.0167

Step-by-step explanation:

Line 1 produces twice as many bags as line 2. Let x be the number of bags produced by line 2.

No. of bags produced by line 2 = x

No. of bags produced by line 1 = 2x

Probability that the bag has been produced by line 1 can be written as:

P(Line 1) = No. of bags produced by line 1/Total no. of bags

             = 2x/(x+2x)

             = 2x/3x

P(Line 1) = 2/3. Similarly,

P(Line 2) = x/3x

P(Line 2) = 1/3

1% bags produced by line 1 are defective so the probability of line 1 producing a defective bag is:

P(Defective|Line 1) = 0.01

3% of bags from line 2 are defective, so:

P(Defective|Line 2) = 0.03

b. The probability that the chosen bag is defective can be calculated through the conditional probability formula:

P(A|B) = P(A∩B)/P(B)

<u>P(A∩B) = P(A|B)*P(B)</u>

The chosen defective bag can be either from line 1 or from line 2. So, the probability that the chosen bag is defective is:

P(Bag is Defective) = P(Defective and from Line 1) + P(Defective and from Line 2)

                                = P(D∩Line 1) + P(D∩Line 2)

                                = P(Defective|Line 1)*P(Line 1) + P(Defective|Line 2)*P(Line 2)

                                = (0.01)*(2/3) + (0.03)(1/3)

P(Bag is Defective) = 0.0167

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2 years ago
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Answer:

The probability is 0.2650

Step-by-step explanation:

Let's start assuming that men and women come in at the same rate.

Let's define the following random variables :

X : ''Number of people that enter a drugstore''

M : ''Number of men that enter a drugstore''

W : ''Number of women that enter a drugstore''

The number of people will be the number of men plus the number of women

⇒

X = M + W

We are also assuming that M and W are independent random variables.

X ~ Po (10)

M ~ Po (λ1)

W ~ Po (λ2)

λ1 = λ2 because we assumed that men and women come in at the same rate.

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P(M\leq 3)=\frac{5^{0}}{0!}e^{-5}+\frac{5^{1}}{1!}e^{-5}+\frac{5^{2}}{2!}e^{-5}}+\frac{5^{3}}{3!}e^{-5}

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Answer:

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If she makes a minimum profit, we need to use the symbol \geq, which indicates minimum quality.

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