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Delvig [45]
1 year ago
11

A fitness club holds an open house for new members. The club expects 6,500 people to sign up for gym membership. If there is a p

ercent error of 4%, what is the range of the number of people who will sign up for gym membership?
Enter the correct answers in the boxes.

Least number of people:

Greatest number of people:
Mathematics
2 answers:
Nata [24]1 year ago
5 0
Firstly, 6500 divided by 100 then x by 4= 260, 260 + 6500= 6760.
The greatest amount is 6760
Then you do 6500-260= 6240
The least amount is 6240
Sunny_sXe [5.5K]1 year ago
3 0
The answer would be 6240 have a good day!
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Answer:

\large\boxed{y=\dfrac{2}{3}}

Step-by-step explanation:

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Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

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6 0
1 year ago
t​ Technodynamics, Inc., a​ randomly-selected hiring committee of 3 people is formed from a group of 4 employees in marketing an
atroni [7]

Answer: a) 0.25, b) 0.78, c) 0.71

Step-by-step explanation:

Since we have given that

Number of employees in marketing = 4

Number of employees in management = 7

We need to hire committee of 3 people.

​a) Find the probability that the committee has exactly 2 employees from marketing.

So, Probability becomes

\dfrac{^4C_2\times ^7C_1}{^{11}C_3}\\\\=\dfrac{42}{165}\\\\=0.25

​b) Find the probability that the committee has at least one employee from marketing.

P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-\dfrac{^7C_3}{^{11}C_3}=1-0.212=0.78

c) Find the probability that the committee has at most one employee from management.

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8 0
1 year ago
Laurissa rolls two number cubes, each with the numbers 1 through 6. Laurissa adds the numbers that appear in the roll. Which two
defon

Answer:

Let's analyze the possible sums of both dices, i will use the notation:

Dice1 + Dice 2 = sum.

also remember that we have 2 dices, with 6 options each.

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I will start at the extremes, the minimum that we can sum is 2, and the maximum is 12, then:

We can have 2 if:

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so 2 and 12 have the same chance (1 out of 36)

now, to have 3 we can have:

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or

1 + 2 = 3.

and to have 11

5 + 6 = 11

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Again, 3 and 11 have the same probability (2 out of 36 options)

And now we can see a pattern.

4 and 10 will have the same chance.

5 and 9 will have the same chance

6 and 8 will have the same chance

7 is the only number that has an unique chance (and it has the largest one)

3 0
2 years ago
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