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Delvig [45]
2 years ago
11

A fitness club holds an open house for new members. The club expects 6,500 people to sign up for gym membership. If there is a p

ercent error of 4%, what is the range of the number of people who will sign up for gym membership?
Enter the correct answers in the boxes.

Least number of people:

Greatest number of people:
Mathematics
2 answers:
Nata [24]2 years ago
5 0
Firstly, 6500 divided by 100 then x by 4= 260, 260 + 6500= 6760.
The greatest amount is 6760
Then you do 6500-260= 6240
The least amount is 6240
Sunny_sXe [5.5K]2 years ago
3 0
The answer would be 6240 have a good day!
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How do you solve this? Please help me (i will give you 14 points)
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Answer:

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Step-by-step explanation:

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The number of people that enter a drugstore in a given hour is a Poisson random variable with parameter λ = 10. Compute the cond
Nonamiya [84]

Answer:

The probability is 0.2650

Step-by-step explanation:

Let's start assuming that men and women come in at the same rate.

Let's define the following random variables :

X : ''Number of people that enter a drugstore''

M : ''Number of men that enter a drugstore''

W : ''Number of women that enter a drugstore''

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⇒

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We are also assuming that M and W are independent random variables.

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M ~ Po (λ1)

W ~ Po (λ2)

λ1 = λ2 because we assumed that men and women come in at the same rate.

λ1 = λ2 = λ

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Because X is the sum of two independent Poisson random variables.

We are looking for :

P(M\leq 3/W=10)=P(M\leq 3)

Because we assume independence.

P(M\leq 3)= P(M=0)+P(M=1)+P(M=2)+P(M=3)

P(M=m)=\frac{5^{m}}{m!}e^{-5} because is a Poisson random variable with λ = 5

P(M\leq 3)=\frac{5^{0}}{0!}e^{-5}+\frac{5^{1}}{1!}e^{-5}+\frac{5^{2}}{2!}e^{-5}}+\frac{5^{3}}{3!}e^{-5}

P(M\leq 3)=e^{-5}+5e^{-5} +(\frac{25}{2})e^{-5} +\frac{125}{6}e^{-5}=0.2650

P(M\leq 3)=0.2650

5 0
2 years ago
What new topics did Isaac Newton discover?
solong [7]
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2 years ago
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solong [7]

Answer:

The system of three equations is equal to

x+y+z=155

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Step-by-step explanation:

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we know that

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