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shusha [124]
2 years ago
15

When you select a random person, the probability that this person will go to Ches

Mathematics
1 answer:
insens350 [35]2 years ago
6 0

Answer: a= 0.0231

Step-by-step explanation:

n=8

p=0.75

q=1 - 0.75 = 0.25

(p=x)

p(5) = 8C5 (0.25)^5 (0.75)^8-5

p(5)= 0.0231

Or 2.31%

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Statements and reasonings 2(4x+2)=20
Katarina [22]

distribute-   8x+4=20

subtract-    8x=20

divide-      20/8=x

answer-   x=2.5


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2 years ago
What is the measure of ∠EGF?<br><br><br><br> What is the measure of ∠CGF?
andrey2020 [161]
<span>measure of ∠EGF = 1/2( 180 - 50)
= 1/2(130)
= 65

</span><span>the measure of ∠CGF = 180 - 65
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2 years ago
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Alan has to pay Robin $48, but he has only $36 with him. Alan overdraws the remaining amount from the bank to pay Robin. After p
Rashid [163]
I assume his account balance will become negative. With no overdraft fees in the question, then his account balance should be $-12. 
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2 years ago
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Which of the following could be the ratio of the length of the longer leg of a 30-60-90 triangle to the length of its hypotenuse
Aliun [14]

Answer:

Option C is correct.

Ratio of longer leg to hypotenuse is;  \sqrt{3} : 2

Step-by-step explanation:

This is the special right angle triangle 30°-60°-90°  as shown below in the figure.

  • The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
  • The side opposite the 60° angle will be the longer leg, because 60 degrees is the mid-sized degree angle in this triangle.
  • Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.

In 30°−60°−90° right triangle,

  • the length of the hypotenuse is twice the length of the shorter leg,also
  • the length of the longer leg is \sqrt{3} times the length of the shorter leg.

Then:

the sides are in proportion i.e,  1:\sqrt{3} :2

Therefore, the ratio of the length of the longer leg to the length of its hypotenuse is:  \sqrt{3} : 2



7 0
2 years ago
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The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.3t^4 + 1100 where t is the time
Montano1993 [528]
The maximum occurs when the derivative of the function is equal to zero.
P(t)=-0.3t^{4}+130t+1100 \\ P'(t)=-1.2t^{3}+130 \\ 0=-1.2t^{3}+130 \\ 1.2t^{3}=130 \\ t^{3}= \frac{325}{3}  \\ t=4.76702
Then evaluate the function for that time to find the maximum population.
P(t)=-0.3t^{4}+130t \\ P(4.76702)=-0.3*4.76702^{4}+130*4.76702+1100 \\ P(4.76702)=1564.79201
Depending on the teacher, the "correct" answer will either be the exact decimal answer or the greatest integer of that value since you cannot have part of a rabbit.
7 0
2 years ago
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