Answer:
a for saturn is 9.55 astronomical units
Step-by-step explanation:
Here, we are interested in calculating the distance from the sun.
Mathematically, from the question;
P = a^3/2
29.5 = a^3/2
a = 29.5^2/3
a = [3√(29.5)]^2
a = 9.55 in astronomical units
Answer: The ΔVZX and ΔWXZ are not congruent by SAS.
Explanation:
It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.
Draw a figure as shown below,
According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.
From the given figure it is easily noticed that in ΔVZX and ΔWXZ,
(given)
(given)
(common side)
Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.
Therefore, the ΔVZX and ΔWXZ are not congruent by SAS.
Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.
Since there are two dice, the total possible outcome is 36.
Hence, the probability of getting one number each is 1/36
Hence, the principal used a fair method because each result is an equally likely possible outcome.
Option B is correct.
Volume of a cylinder = π r² h
Given:
radius = (x+8)
height (2x + 3)
Volume of a cylinder = π * (x+8)² * (2x + 3)
V = π * (x+8)(x+8) * (2x+3)
V = π * (x² + 8x + 8x + 64) * (2x + 3)
V = π * (x² + 16x + 64) * (2x + 3)
V = π * (2x³ + 32x² + 128x + 3x² + 48x + 192)
V = π * (2x³ + 32x² + 3x² + 128x + 48x + 192)
V = π * (2x³ + 35x² + 176x + 192)
Answer:
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
