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2 years ago

A sweater that normally costs $32.00 is on sale for $24.00. What is the percent

Mathematics

1 answer:

Vlad1618 [11]2 years ago

6 0

Answer:

25 %

Step-by-step explanation:

Percentage is given by :

$\%=\dfrac{\text{original value-new value}}{\text{origial value}}\times 100$

Original cost of sweater is $32 and sale cost is $24. So,

$\%=\dfrac{32-24}{32}\times 100\\\\=25\%$

Hence, 25 % is the markdown on the sweater.

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The chance she will pull out a red paper is 20%.

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2 years ago

Leona purchased a $1,000 bond having a quoted price of 99.875. She had to pay a 5.5% brokerage fee (of the selling price). What

Zina [86]

Answer:

The total cost of the bond is none of the given choices.

Step-by-step explanation:

The selling price of a $1000 bond = $99.875

The brokerage fee = 5.5 %

Now, 5.5% of $99.875 = $\frac{5.5}{100} \times 99.875 = 5.493$

So, the brokerage fee = $5.493

Now, to find out the total cost of the bond:

Total Cost = The selling Price + Brokerage Price

= $99.875 + $5.493

= $105.368

or, the total price of the $1000 bond is $ 105.368.

Hence, the total cost of the bond is none of the given choices.

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2 years ago

If -50c+6=-69, what is the value of 6c-15

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The answer that I got is C=-6

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2 years ago

What is (0.5x + 15) + (8.2x- 16.6)

nadya68 [22]

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2 years ago

Suppose that in a survey of 1,000 U.S. residents, 721 residents believed that the amount of violent television programming had i

Art [367]

Answer: 0.813

Step-by-step explanation:

Let A be the event describes the number of residents believed that the amount of violent television programming had increased over the past 10 years.

& B be the event describes the number of residents believed that the amount of violent television programming had decreased over the past 10 years.

Given : n(A)=721 ; n(B)=454 ; n(A∩B)=362

We know that ,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

i.e. $n(A\cup B)=721+454-362=813$

Also, the total number of U.S. residents surveyed n(S)= 1,000

Then, the proportion of the 1,000 U.S. residents believed that either the amount of violent programming had increased or the overall quality of programming had decreased over the past 10 years will be :-

$P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}=\dfrac{813}{1000}=0.813$

Hence, the required answer = 0.813

3 0

2 years ago