Answer:
This is possible.
Step-by-step explanation:
We can say that m<E=m<E, because of the Reflexive Property
Then, we have angles JKL and ELJ, which are equal through the peripheral angle theorem.
With these two angles, we can say that triangles ELK and EJL are similar, by the Angle-Angle Postulate (AA).
Then we can create this ratio through the Corresponding Parts of Similar Triangles Theorem, (CPST),
.
With this ratio, we can cross multiply to get the desired result
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Hope this helps with your RSM problem
Yup, i caught ya.
Answer:
(3 x + 2) (5 x - 4)
Step-by-step explanation:
Factor the following:
15 x^2 - 2 x - 8
Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):
5 x (3 x + 2) - 4 (3 x + 2)
Factor 3 x + 2 from 5 x (3 x + 2) - 4 (3 x + 2):
Answer: (3 x + 2) (5 x - 4)
Answer:
a) 1/10 x 5/10 = 1/20
b) 1/10 x 5/9 = 1/18
Step-by-step explanation:
Answer:
StartRoot 53 EndRoot units
XY = √53
Step-by-step explanation:
Choose which is point 1 and point 2 so you don't confuse the coordinates.
Point 1 (–4, 0) x₁ = –4 y₁ = 0
Point 2 (3, 2) x₂ = 3 y₂ = 2
Use the formula for the distance between two points.




Therefore the line of segment XY is √53.
The odds of rolling a 4 is 1/6 or 0.16667 or 16%