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seropon [69]
1 year ago
9

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

ctor field is not conservative, enter dne.) f(x, y, z) = 6xy2z2i + 4x2yz3j + 6x2y2z2k
Mathematics
1 answer:
sweet [91]1 year ago
3 0
A conservative vector field \mathbf f has curl \nabla\times\mathbf f=\mathbf0. In this case,

\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0

so the vector field is not conservative.
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It is given that:

Circle 1 has center (−4, −7) and a radius of 12 cm.

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