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Marina86 [1]
2 years ago
5

Trapezoid A B C D is shown. Sides A B and D C are parallel. Sides A D and B C are congruent. Angle B is (3 x) degrees and angle

D is (9 x) degrees. What is the value of x in trapezoid ABCD? x=15 x=20 x=45 x=60
Mathematics
2 answers:
photoshop1234 [79]2 years ago
4 0

Answer: The value of x in trapezoid ABCD is 15

Step-by-step explanation: The trapezoid as described in the question has two bases which are AB and DC and these are parallel. Also it has sides AD and BC described as congruent (that is, equal in length or measurement). These descriptions makes trapezoid ABCD an isosceles trapezoid.

One of the properties of an isosceles trapezoid is that the angles on either side of the two bases are equal. Since line AD is equal to line BC, then angle D is equal to angle C. It also implies that angle A is equal to angle B.

With that bit of information we can conclude that the angles in the trapezoid are identified as 3x, 3x, 9x and 9x.

Also the sum of angles in a quadrilateral equals 360. We can now express this as follows;

3x + 3x + 9x + 9x = 360

24x = 360

Divide both sides of the equation by 24

x = 15

Therefore, in trapezoid ABCD

x = 15  

STatiana [176]2 years ago
4 0

Answer:

x=15

Step-by-step explanation:

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Proportion which can be used to represent equivalency of 3 feet in 1 yard and 12 feet in 4 yard is 3 : 1 : : 12 : 4

<h3><u>Solution:</u></h3>

Given that

There are 3 feet in one yard  

And there are 12 feet in 4 yard  

Number of feet in one yard = 3 that is feet  : yard = 3 : 1  

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3 0
2 years ago
Pq=6x+25 and qr=16-3x; find pr
Viktor [21]

Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}

If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.

Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:

\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41

Conclusion:

\overline{PR} \; is \; represented \; the \; expression \; 3x +41

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