As a general rule to solve the problem we are going to transform all values to the lower unit.
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m
b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m
c. 44 m – 5 dm
44 m - 0.5 m = 43.5 m
d. 73 km 47 hm 2 dam - 11 km 55 hm
73,000 m 4,700 m 20 m - 11,000 m 5,500 m
77,720 m - 16,500 m = 61,220 m
You have to make a system of equations: lets make a equal the amount marry makes per student and b be her base amount.
90=15a+b (you have to subtract the top equation by the bottom equation)
62=8a+b (90-62=28, 15a-8a=7a, and b-b=0)
Since b canceled out, you are left with 7a=28 which means a=4. you can than plug a into the equation 62=8a+b to find that b=30.
since Lisa makes half of the base amount marry, her base amount is 15. However, she also make twice the amount per kid so she makes 8 per kid.
using the found values found you can make the equations (m=the amount Marry makes, l=the amount Lisa makes, and c is the number of children)
m=4c+30
l=8c+15
set c=20 and you should get m=110 and l=175. Based off of that information, we can say that Lisa makes more money instructing a class of 20 students.
I hope this helps.
Answer:
9 teams
Step-by-step explanation:
If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.
36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))
using this knowledge, we can then count up:
1+2+3+4+5+6+7+8 = 36
If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.
Answer:
at x = 10, 
Step-by-step explanation:
The given equation is 
Here, lets substitute the value of x = 10
So, the equation simplifies to ,
= (4 x 100) + 170 + 2 = 400 + 170 + 2
= 572
So, at x = 10, 
