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Zepler [3.9K]
2 years ago
9

Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the

pre-image if the coordinates of point D’ in the image are (9, –8)?
a) (13, –23)
b) (5, 7)
c) (18, 1)
d) (–6, –4)
Mathematics
2 answers:
Vitek1552 [10]2 years ago
6 0
The correct answer is B.
alisha [4.7K]2 years ago
4 0
The translation is (x-4, y+15)

This means you would subtract 4 from the X coordinate and add 15 to the y coordinate.
 The original coordinates is (9,-8) 

The first number is X and the 2nd number is Y.

9-4 = 5

-8+15 = 7

The new location would be (5,7)

The answer is B.

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Answer:

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Step-by-step explanation:

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\vec{a}(t)=\frac{dv}{dt}=\frac{d}{dt}(8)\overrightarrow{i}+\frac{d}{dt}(16t)\overrightarrow{j}+\frac{d}{dt}(6)\overrightarrow{k}=0\overrightarrow{i}+16\overrightarrow{j}+0\overrrighatarrow{k}.

The velocity at t=0 is \vec{v}(0)=8\overrightarrow{i}+0\overrightarrow{j}+6\overrighatarrow{k}.

The speed at t=0 is \lVert \vec{v}(0)\rVert =10. Then, the velocity at t=0 written as a product of the speed at t=0 and the direction at t=0 is

\vec{v}(0)=\lVert \vec{v}(0)\rVert \dfrac{\vec{v}(0)}{\lVert \vec{v}(0)\rVert}=10\cdot(\dfrac{8}{10},0,\dfrac{6}{10}).

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