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Zepler [3.9K]
1 year ago
9

Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the

pre-image if the coordinates of point D’ in the image are (9, –8)?
a) (13, –23)
b) (5, 7)
c) (18, 1)
d) (–6, –4)
Mathematics
2 answers:
Vitek1552 [10]1 year ago
6 0
The correct answer is B.
alisha [4.7K]1 year ago
4 0
The translation is (x-4, y+15)

This means you would subtract 4 from the X coordinate and add 15 to the y coordinate.
 The original coordinates is (9,-8) 

The first number is X and the 2nd number is Y.

9-4 = 5

-8+15 = 7

The new location would be (5,7)

The answer is B.

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D .........is the answer
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∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place?
never [62]

Answer: The answer is (D) Reflection across the line y = -x.


Step-by-step explanation:  In figure given in the question, we can see two triangles, ΔABC and ΔA'B'C' where the second triangle is the result of transformation from the first one.

(A) If we rotate ΔABC 180° counterclockwise about the origin, then the image will coincide with ΔA'B'C'. So, this transformation can take place here.

(B) If we reflect ΔABC across the origin, then also the image will coincide with ΔA'B'C' and so this transformation can also take place.

(C) If we rotate ΔABC through 180° clockwise about the origin, the we will see the image will be same as ΔA'B'C'. Hence, this transformation can also take place.

(D) Finally, if we reflect ΔABC across the line y = -x, the the image formed will be different from ΔA'B'C', in fact, it is ΔA'D'E', as shown in the attached figure. So, this transformation can not take place here.

Thus, the correct option is (D).


6 0
1 year ago
Read 2 more answers
In isosceles triangle ∆ABC, BM is the median to the base AC . Point D is on BM . Prove the following triangle congruencies:∆ABD
Alex787 [66]

Answer:

In isosceles triangle ABC, BM is the median to the base AC and Point D is on  BM as shown below in the figure;

Median of a triangle states that a line segment joining a vertex to the midpoint of the opposing side, bisecting it

M is the median of AC

then by definition;

AM = MC                 ......[1]

In  ΔAMD and  ΔDMC

AM = MC             [side]                [By [1]]

\angle AMD = \angle DMC =90^{\circ}    [Angle]

DM =DM       [Common side]      

Side-Angle-Side postulate(SAS) states that if  two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

Then, by SAS,

\triangle AMD \cong \triangle DMC

CPCT stands for Corresponding parts of congruent triangles are congruent

By CPCT,  

AD = DC       [Corresponding side]                   ......[2]

In  ΔABD and  ΔCBD

AB = BC   [Side]                      [By definition of isosceles triangle]

BD= BD   [common side]      

AD = DC [Side]                         [by [2]]

Side-Side-Side(SSS) postulate states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Therefore, by SSS theorem,

\triangle ABD \cong \triangle CBD    


4 0
1 year ago
Read 2 more answers
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

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