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1 year ago

9

A restaurant has a special whereby both parents can eat for $20 and each child can eat for $5. Assuming a family group consists

of both parents and at least one child, what is the maximum number of family groups that could have attended given that the restaurant took $115?

2 answers:

nordsb [41]1 year ago

5 0

4groups of adults and 7 kids

vodomira [7]1 year ago

3 0

The answer is 2.55555555555556
This is because there are 2 parents so 20 * 2 = 40 We have 1 child. = 5
= 45
So 115 / 45= 2.55555555556
I hope this helps and please make this the Brainliest answer.
:)

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The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

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Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

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C. JKM is not a right triangle because KM ≠ 15.3.

Step-by-step explanation:

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We will find length of side KM using our right triangles JLM and JLK as $KM=KL+LM$ .

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