Tony scored 22 and 25 points in the first two games of a basketball tournament. Tony’s goal is to make the all tournament team.
1 answer:
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Answer:
The ticket price that maximizes revenue is $50.
The maximum monthly revenue is $250,000.
Step-by-step explanation:
We have to write a function that describes the revenue of the airline.
We know one point of this function: when the price is $30, the amount of passengers is 7000.
We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.
Then, we can write the revenue as the multiplication of price and passengers:
where x is the variation in the price of the ticket.
Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.
We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:
The maximum monthly revenue is:
Answer:
(a) 2.29 km/h
(b) 9 km/h
Step-by-step explanation:
For part (a) you have to apply<em> the average speed formula</em>, which is defined by:
where d is the total distance traveled and t is the total time needed.
km/h
For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:
The nap time in hours is:
90/60 = 1.5 h (because there are 60 minutes in one hour)
The running time is:
T= 1.75 - 1.5 = 0.25 h
Let t1 represent the time before the nap and t2 the time after the nap:
t1+t2 = T
t1+t2 = 0.25
You have to apply the formula d=vt before and after the nap:
-Before the nap, the distance traveled was 0.50 km
0.50 = v1t1
-Afer the nap, the distance traveled was 3.50 km
3.50=v2t2
But v2=2v1 (because after the nap the rabbit runs twice as fast)
You have to solve the system of equations:
t1=0.25-t2 (I)
v1t1=0.50 (II)
2v1t2=3.50 (III)
Replacing (I) in (II)
v1(0.25-t2)=0.50
Applying distributive property and solving:
0.25v1-v1t2=.050
For (III) you have that v1t2=3.50/2=1.75. Hence:
0.25v1-1.75=0.50
Solving for v1:
v1 = 9 km/h