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aivan3 [116]
1 year ago
13

About 1.75 million people live in a circular region with a 15-mile diameter. Find the population density in people per square mi

le. Round your answer to the nearest whole number.
Mathematics
2 answers:
fredd [130]1 year ago
7 0

The diameter of the circular region is 15 miles

that gives radius = 7.5 miles

Now,

Area = π r² = 3.14 * 7.5* 7.5

= 176.625 mile²

Population density = number of people / land area

this is =  \frac{1750000}{176.625} = 9907.997

Now rounding off to nearest whole number, we get 9908

So, there  are 9908 population living in per square mile.

matrenka [14]1 year ago
3 0

The diameter of the circular region is 15 miles

that gives radius = 7.5 miles

Now,

Area = π r² = 3.14 * 7.5* 7.5

= 176.625 mile²

Population density = number of people / land area

this is =  \frac{1750000}{176.625} = 9907.997

Now rounding off to nearest whole number, we get 9908

So, there  are 9908 population living in per square mile.

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Answer: D


you have to distribute
3 times 5/4n = 3.75n
3 times 1.8 = 5.4
you can’t add both products because they don’t have like terms
3.75n + 5.4
3 0
1 year ago
For any linear function f(x) = mx + b, when does kf(x) = f(kx)?
sammy [17]
A linear function. Sorry of it's not en
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2 years ago
Given: ∠BCD is right; BC ≅ DC; DF ≅ BF; FA ≅ FE Triangles A C D and E C B overlap and intersect at point F. Point B of triangle
Aloiza [94]

Answer:

1) ΔCBF ≅ ΔCDF by (SSS)

2) ΔBFA ≅ ΔDFE by (SAS)

3) ΔCBE ≅ ΔCDA by (HL)

Step-by-step explanation:

1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;

ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency

2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)

Therefore;

ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency

3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF

Where:

EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively

We have that;

EB = AD from  FE + BF = FA + DF

Where we also have BC ≅ DC

Where:

BC and DC are the legs of ΔCBE and ΔCDA respectively

Then we have the following relation;

ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).

4 0
1 year ago
Read 2 more answers
Len made 1 1/3 liters of punch. He added 2/5 liters of water to make the punch. How much water was used for each liter of punch?
Sergio039 [100]

Answer:

  3/10 liter

Step-by-step explanation:

Assuming your description means that 4/3 liters of punch includes 2/5 liters of water, then the fraction of punch that is water is ...

  (2/5)/(4/3) = (2/5)(3/4) = 3/10

3/10 of a liter of water is used in each liter of punch.

5 0
2 years ago
An ideal gas is confined within a closed cylinder at a pressure of 2.026 × 105 Pa by a piston. The piston moves until the volume
Elis [28]

Answer:

The final pressure of the gas when its temperature returns to its initial value 1.8234\times 10^6 Pa.

Step-by-step explanation:

Given : An ideal gas is confined within a closed cylinder at a pressure of 2.026\times 10^5 Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.

To find : What is the final pressure of the gas when its temperature returns to its initial value?

Solution :

Since the temperature is constant .

The relation between P and V is given by,

P_1\times V_1 = P_2\times V_2

\frac{P_1}{P_2}=\frac{V_2}{V_1} ....(1)

The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. V_2=\frac{V_1}{9}

or \frac{V_2}{V_1}=\frac{1}{9}

P_1=2.026\times 10^5

Substitute in equation (1),

\frac{2.026\times 10^5}{P_2}=\frac{1}{9}

P_2=9\times 2.026\times 10^5

P_2=18.234\times 10^5

P_2=1.8234\times 10^6

The final pressure of the gas when its temperature returns to its initial value 1.8234\times 10^6 Pa.

5 0
1 year ago
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