Answer: D
you have to distribute
3 times 5/4n = 3.75n
3 times 1.8 = 5.4
you can’t add both products because they don’t have like terms
3.75n + 5.4
A linear function. Sorry of it's not en
Answer:
1) ΔCBF ≅ ΔCDF by (SSS)
2) ΔBFA ≅ ΔDFE by (SAS)
3) ΔCBE ≅ ΔCDA by (HL)
Step-by-step explanation:
1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;
ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency
2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)
Therefore;
ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency
3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF
Where:
EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively
We have that;
EB = AD from FE + BF = FA + DF
Where we also have BC ≅ DC
Where:
BC and DC are the legs of ΔCBE and ΔCDA respectively
Then we have the following relation;
ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).
Answer:
3/10 liter
Step-by-step explanation:
Assuming your description means that 4/3 liters of punch includes 2/5 liters of water, then the fraction of punch that is water is ...
(2/5)/(4/3) = (2/5)(3/4) = 3/10
3/10 of a liter of water is used in each liter of punch.
Answer:
The final pressure of the gas when its temperature returns to its initial value
Pa.
Step-by-step explanation:
Given : An ideal gas is confined within a closed cylinder at a pressure of
Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.
To find : What is the final pressure of the gas when its temperature returns to its initial value?
Solution :
Since the temperature is constant
.
The relation between P and V is given by,

....(1)
The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. 
or 

Substitute in equation (1),
The final pressure of the gas when its temperature returns to its initial value
Pa.