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1 year ago

A university is trying to determine what price to charge for tickets to football games. At a price of $30 per ticket,

Mathematics

1 answer:

kykrilka [37]1 year ago

7 0

Answer:

The price should be 25 dollars, with this price 50000 people will attend the game.

Step-by-step explanation:

To solve this question we can build a table in which we compare the information taking into account the price of the ticket, the average number of people, the earnings for the sale of the tickets and the earnings of the sales in the concessions and with this determine the maximize revenue that corresponds to the best options for the university so as you can see in the attachment.

To calculate the average people we subtract 10000 per each decrease in $5.

To calculate the earnings per sales we have to multiply the cost of the ticket by the number of average people

To calculate the earnings per concessions we have to multiply the spends in the concessions by the average people

To calculate the total earnings we have to add the earnings per sales with the earnings per concessions.

As you can see, the total earnings for ticket price of $25 and $20 are the same ($150,000) if we increase or decrease the price of the tickets, the total earnings will decrease, then we have to choose the best option.

For maintaining the security and the infrastructure, it will be better to have less people, then the most convenient option will be that in which 50,000 people attend to the game, and for this, the price will be of $25.

Then, the price should be 25 dollars, with this price 50000 people will attend the game.

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Condense each expression. 5 log5 x - 1/4 log5 (8 -x)

allsm [11]

Step-by-step explanation:

5 log₅ x − ¼ log₅ (8−x)

log₅ x⁵ − log₅ (8−x)^¼

log₅ x⁵ − log₅ ∜(8−x)

log₅ (x⁵ / ∜(8−x))

4 0

2 years ago

Rocío trabaja en una peluquería, le pagan $50 por corte realizado, adicionalmente recibe $25 al día. Si el día miércoles recibió

skad [1K]

Usando conceptos de funciones lineales, se encuentra que hizo 5 cortes.

----------------

Una funcion lineale tiene el seguiente formato:

$y(x) = ax + b$

En que:

a eres lá inclinacion, o sea, lo que es pago por cada corte.
b eres el intercepto, o sea, lo pagamiento fixo por día.

----------------

Pagan $50 por corte realizado, o sea, $a = 50$ .
$25 fixo al día, o sea, $b = 25$

Entonces, la funcion de su recibimiento y, como funcion de su numero de cortes x, es da por:

$y(x) = 25 + 50x$

----------------

Recibió $275, o sea, $y(x) = 275$

Entonces, el numero de cortes es:

$y(x) = 25 + 50x$

$25 + 50x = 275$

$50x = 250$

$x = \frac{250}{50}$

$x = 5$

Realizó 5 cortes.

Un problema similar se encuentra en brainly.com/question/18070326

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2 years ago

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Consider the probability distribution of x, where x is the number of job applications completed by a college senior through the

Oksi-84 [34.3K]

The expected number out of 1000 selected college seniors that completed 1 job application through the career centers is given by 0.011 x 1000 = 11 which is close to 14.

The expected number out of 1000 selected college seniors that completed 2 job application through the career centers is given by 0.115 x 1000 = 115 which is far away from 15.

The expected number out of 1000 selected college seniors that completed 3 job application through the career centers is given by 0.123 x 1000 = 123 which is close to 130.

Therefore, the result that would be suprising is "15 seniors completed 2 job applications through the career center."

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2 years ago

Simplify" (0.324/4.76+ 6.3)^-3

tamaranim1 [39]

Answer:

i think its six :)

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2 years ago

A certain company's main source is a mobile app. The function h models the company's annual profit (in million of dollars) as a

cricket20 [7]

Answer:

At price 3 and 11, the profit will be $0

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em> A certain companies main source of income is a mobile app. The companies annual profit (in millions of dollars) as a function of the app’s price (in dollars) is modeled by P(x)=-2(x-3)(x-11) which app prices will result in $0 annual profit?</em>

My answer:

Given:

x is the app price
P(x) is the profit earned

If we want to find out the app price that will result in $0 annual profit? It means we need to set the function:

P(x)=-2(x-3)(x-11) = 0

<=> (x-3)(x-11)= 0

<=> x - 3 = 0 or x - 11=0

<=> x = 3 or x = 11

So at price 3 and 11, the profit will be $0

Hope it will find you well.

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1 year ago

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