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Pani-rosa [81]
2 years ago
8

If ∆JKL ≅ ∆PQR, which one of these is not a pair of corresponding parts? ​∠J and ∠P​ and ​∠L and ∠R​ and

Mathematics
1 answer:
Mandarinka [93]2 years ago
8 0
When trying to prove that two triangles are congruent there are three congruency rules SAS, ASA and SSS. From the looks of things though I would say it would be the third one because just from the way you named the triangles I could tell that the two angles could correspond.

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Ashley plants a tree 45cm tall it grows by 10 cm each year. Find the amount ashley gets in the 5th year?​
Genrish500 [490]

Answer:

95cm

Step-by-step explanation:

45cm is the initial height

each year grow 10cm

growing time 5 years

45+(10 × 5)=95 cm

4 0
2 years ago
If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
alexandr1967 [171]

Answer:

<h2>The domain is all real values of x except \frac{4}{5}.</h2>

Step-by-step explanation:

The function, f(x) = \frac{x - 3}{x}.

g(x) = 5x - 4.

Hence, (f circle g) (x) = \frac{5x - 4 - 3}{5x - 4}.

We need to find the domain of (f circle g) (x) .

The domain means the set of values of x, for which we will get a real value of (f circle g) (x).

The function will not give a real value when, 5x - 4 = 0 that is x = \frac{4}{5}.

Hence, the domain of the function will be all real values of x rather than \frac{4}{5}.

5 0
2 years ago
Read 2 more answers
Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa
WITCHER [35]
<span>65 = number of different arrangements of 2 and 3 card pages such that the total number of card slots equals 18. 416,154,290,872,320,000 = number of different ways of arranging 18 cards on the above 65 different arrangements of page sizes. ===== This is a rather badly worded question in that some assumptions aren't mentioned. The assumptions being: 1. The card's are not interchangeable. So number of possible permutations of the 18 cards is 18!. 2. That all of the pages must be filled. Since the least common multiple of 2 and 3 is 6, that means that 2 pages of 3 cards can only be interchanged with 3 pages of 2 cards. So with that said, we have the following configurations. 6x3 card pages. Only 1 possible configuration. 4x3 cards and 3x2 cards. These pages can be arranged in 7!/4!3! = 35 different ways. 2x3 cards and 6x2 cards. These pages can be arranged in 8!/2!6! = 28 ways 9x2 card pages. These can only be arranged in 1 way. So the total number of possible pages and the orders in which that they can be arranged is 1+35+28+1 = 65 possible combinations. Now for each of those 65 possible ways of placing 2 and 3 card pages such that the total number of card spaces is 18 has to be multiplied by the number of possible ways to arrange 18 cards which is 18! = 6402373705728000. So the total amount of arranging those cards is 6402373705728000 * 65 = 416,154,290,872,320,000</span>
6 0
2 years ago
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One is making 15,000 and the other is making 13,000 so yeah hope this is what you were looking for                                                     ^                                                                                                                                            ! 
5 0
2 years ago
Tiffany ate 1/4 of a pizza. If there were 16 slices of pizza to begin with, how many slices did Tiffany eat?​
viktelen [127]

Answer:

Tiffany ate 4 slices of pizza

Step-by-step explanation:

1/4 of 16 is 4

6 0
2 years ago
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