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wlad13 [49]
2 years ago
8

Stadium has a direct staffing cost of $108,000. Overhead costs (Social Security Medicare workers compensation etc.)cost to see h

im in additional 15% what is the total staffing costs
Mathematics
2 answers:
grigory [225]2 years ago
7 0
108,000x.15=16,200 therefor u should have the right answer bud hope it helps
xz_007 [3.2K]2 years ago
6 0

The direct staffing cost is given by $108,000

Total cost of staffing = Direct staffing cost + overhead cost

Overhead cost = 15% of direct staffing cost

Overhead cost = 0.15 * 108,000= 16,200

So overhead cost of staffing is 16,200 dollars.

Adding this overhead cost to direct staffing cost ,

Total cost = 108,000 +16,200 = 1,24,200

Answer: The total cost of staffing is $1,24,200.

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Adam rolls a number cube with faces numbered 1 to 6. what is the probability, to the nearest hundredth, that he rolls a 4?
AURORKA [14]

To solve this problem, let us first define probability. We know in statistics class that probability is simply the ratio of a selected event to occur over the total number of events. That is:

probability = number of selected event to occur / total number of events

 

In this scenario, our only selected event to occur is to have a dice roll of 4. That is 1 event only. Now since there are 6 number in the dice, therefore the total number of events is 6. Therefore:

probability = 1 / 6

probability = 0.1666667

Rounding off to the nearest hundredth:

<span>probability = 0.17</span>

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2 years ago
Nicole has $9 to spend on card.She finds friends with the same amount of money to split the cost of a set.One set costs $27. Eac
Lostsunrise [7]
They get 3 cards but they all pay 9 dollars
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On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

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3 0
2 years ago
Destiny just received two separate gifts from her great-great-grandmother.
hichkok12 [17]

answer: 6 is the greatest number of snack bags that Destiny can make. Step-by-step

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The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies.

5 0
1 year ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Serga [27]

Answer:

1. W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3. E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.O(10,1),P(6,7),Q(14,9) and R(16,7).

Step-by-step explanation:

We are given that a quadrilateral JKLM with vertices J(8,4),K(4,10),L(12,12) and M(14,10)

We have to match a quadrilateral with its correct transformation of given quadrilateral JKLM

1.a transformation 3 units down and 3 units left

By using transformation rule (x,y)\rightarrow (x-3,y-3)

The new  vertices  of quadrilateral is (5,1), (1,7),(9,9) and (11,7).

Hence, the quadrilateral WXYZ with vertices W(5,1),X(1,7),Y(9,9) and Z(11,7).

2.A sequence of reflection across x- axis and y-axis in order

Reflection across x- axis

The transformation  rule (x,y)\rightarrow (x,-y)

By using this rule

The vertices of quadrilateral are  (8,-4),(4,-10),(12,-12) and (14,-10).

After the reflection across y- axis

The transformations rule

(x,y)\rightarrow (-x,y)

By using this rule

We get the new vertices of quadrilateral are (-8,-4),(-4,-10),(-12,-12) and (-14,-10).

Hence, the quadrilateral ABCD with vertices A(-8,-4),B(-4,-10),C(-12,-12) and D(-14,-10).

3.a translation 3 unit left and 2 units up

The transformation rule (x,y)\rightarrow (x-3,y+2)

By using this rule

The new vertices are (5,6),(1,12),(9,14) and (11,12).

Hence, the quadrilateral EFGH with vertices E(5,6) ,F(1,12),G(9,14) and H(11,12).

4.a translation 2 units right and 3 units down

The transformation rule

(x,y)\rightarrow (x+2,y-3)

By using this rule

The new vertices are (10,1),(6,7),(14,9) and (16,7)

Hence, the quadrilateral OPQR with vertices O(10,1),P(6,7),Q(14,9) and R(16,7).

7 0
2 years ago
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