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2 years ago

If a cheeseburger weighs a half pound on Earth, what will it weigh on Jupiter?

Mathematics

2 answers:

beks73 [17]2 years ago

7 0

If a cheeseburger weighs half a pound on earth, it will be about 1.265 pounds on Jupiter

Katena32 [7]2 years ago

3 0

Answer:

47 pounds i think \/'_'\/

Step-by-step explanation:

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The equation 3w + 4j = 39 is used to determine the number of water bottles w and the number of juice bottles j that can be bough

jarptica [38.1K]

Juice bottles are J, replace j with 6 in the equation and solve for w:

3w + 4(6) = 39

3w + 24 =39

Subtract 24 from both sides:

3w = 15

Divide both sides by 3:

w = 15/3

w = 5

You can buy 5 water bottles.

3 0

2 years ago

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Sten sat on a bench and read a book while Manu was at soccer practice. He read for 35 minutes and stopped at 6:10 p.m.

Dahasolnce [82]

Answer:

5:35

Step-by-step explanation:

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1 year ago

FIRST ONE TO ANSWER GETS BRAINLIEST Henry divided his socks into five equal groups. Let s represent the total number of socks. W

Alex777 [14]

Answer: There are 20 socks in the first case and there are 75 socks in the second case.

Step-by-step explanation:

Since we have given that

Number of equal groups = 5

Let the total number of socks be 's'.

According to question, expression will be

Now, Suppose number of socks in each group = 4

So, it will become,

Suppose number of socks in each group = 15

So, Total number of socks become

Hence, there are 20 socks in the first case and there are 75 socks in the second case.

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2 years ago

The sticker warehouse sells rolls of stickers for $4.00 each. the average custiomer buys six rolls of stickers. the owner finds

Sliva [168]

A) 4 price reductions. B) The maximum predicted sales revenue per customer is $30.25 which occurs with 5 price reductions. As a matter of interest, the $30 revenue per customer also occurs with 6 price reductions but this happens after reaching the maximum predicted revenue per customer of $30.25.

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2 years ago

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A television station plans to ask a random sample of 400 city residents if they can name the news anchor on the evening news at

hodyreva [135]

Answer:

There is an 8.38% probability that the anchor will be fired.

Step-by-step explanation:

For each resident, there is only two possible outcomes. Either they can name the news anchor on the evening news at their station, or they cannot.

This means that the binomial probability distribution will be used in our solution.

However, we are working with samples that are considerably big. So i am going to aaproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X), \sigma = \sqrt{V(X)}$ .

In this problem, we have that:

400 city residents are going to be asked. So $n = 400$ .

Suppose that in fact 12% of city residents could name the anchor if asked. This means that $p = 0.12$ .

So,

$\mu = E(X) = 400*0.12 = 48$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{400*0.12*0.88} = 6.5$ .

They plan to fire the news anchor if fewer than 10% of the residents in the sample can do so.

What is the approximate probability that the anchor will be fired?

10% of the residents is 0.10*400 = 40 residents.

Fewer than 10% is 39 residents. So the probability that the anchor will be fired is the pvalue of Z when $X = 39$ .

So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39 - 48}{6.5}$

$Z = -1.38$

$Z = -1.38$ has a pvalue of 0.0838. This means that there is an 8.38% probability that the anchor will be fired.

5 0

2 years ago